Two identical circular planar surface charges float in free space (permittivity €). The surface charge density is constant over the disk pso (with units As/m²) for both disks. The disks are separated by distance 'a'. Let's fix the coordinate system such that the upper disk is on the xy plane (z 0) and its center lies on the origin. The lower plate is on the xy plane (z = −a). The goal is to find the expression for electric scalar potential at the symmetry axis (z) between the two disks. a Ps0 = Z Pso O A b (a) Determine the scalar potential V(z) at the z axis in between the two disks. Re- member that you need to integrate the effect of all charge in the disk. (Since there are two disks you will need superposition. The cylindrical coordinate sys- tem should be helpful.) Hint: x (B²+x²)¹/2( where C is constant of integration. -dx = √B² + x² + C

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Two identical circular planar surface charges float in free space (permittivity €0). The
surface charge density is constant over the disk pso (with units As/m²) for both disks.
The disks are separated by distance 'a'. Let's fix the coordinate system such that the
upper disk is on the xy plane (z = 0) and its center lies on the origin. The lower
plate is on the xy plane (z = −a). The goal is to find the expression for electric scalar
potential at the symmetry axis (z) between the two disks.
a
Ps0
Ps0
Z
S
O
A
b
(a) Determine the scalar potential V(z) at the z axis in between the two disks. Re-
member that you need to integrate the effect of all charge in the disk. (Since
there are two disks you will need superposition. The cylindrical coordinate sys-
tem should be helpful.)
Hint:
X
(B² + x²)¹/2′
where C is constant of integration.
dx
=
B² + x² + C
Transcribed Image Text:Two identical circular planar surface charges float in free space (permittivity €0). The surface charge density is constant over the disk pso (with units As/m²) for both disks. The disks are separated by distance 'a'. Let's fix the coordinate system such that the upper disk is on the xy plane (z = 0) and its center lies on the origin. The lower plate is on the xy plane (z = −a). The goal is to find the expression for electric scalar potential at the symmetry axis (z) between the two disks. a Ps0 Ps0 Z S O A b (a) Determine the scalar potential V(z) at the z axis in between the two disks. Re- member that you need to integrate the effect of all charge in the disk. (Since there are two disks you will need superposition. The cylindrical coordinate sys- tem should be helpful.) Hint: X (B² + x²)¹/2′ where C is constant of integration. dx = B² + x² + C
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