Two horizontal forces, F, and F,, are acting on a box, but only F, is shown in the drawing. F, can point either to the right or to the left. The box moves only along the x axis. There is no friction between the box and the surface. Suppose that F, = +7.6 N and the mass of the box is 5.0 kg. Find the magnitude and direction of E when the acceleration of the box is (a) +5.3 m/s?, (b) -5.3 m/s?, and (c) 0 m /s². --+x (а) Fz + v 18.9 N. (b) F2 31.8 [N (c) F, -7.6 N.

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Chapter1: Units, Trigonometry. And Vectors
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**Problem Statement:**

Two horizontal forces, \(\vec{F}_1\) and \(\vec{F}_2\), are acting on a box, but only \(\vec{F}_1\) is shown in the drawing. \(\vec{F}_2\) can point either to the right or to the left. The box moves only along the x-axis. There is no friction between the box and the surface. Suppose that \(\vec{F}_1 = +7.6 \, \text{N}\) and the mass of the box is 5.0 kg. Find the magnitude and direction of \(\vec{F}_2\) when the acceleration of the box is:

(a) \(+5.3 \, \text{m/s}^2\),
(b) \(-5.3 \, \text{m/s}^2\), and
(c) \(0 \, \text{m/s}^2\).

**Diagram Explanation:**

In the given diagram:
- A box is shown on a flat, horizontal surface.
- A force \(\vec{F}_1\) is acting on the box towards the right, indicated by a rightward arrow.

**Calculations:**

**(a) When acceleration \(a = +5.3 \, \text{m/s}^2\):**
\[
\sum \vec{F} = m \cdot a
\]
\[
7.6 \, \text{N} + \vec{F}_2 = 5.0 \, \text{kg} \times 5.3 \, \text{m/s}^2
\]
\[
7.6 \, \text{N} + \vec{F}_2 = 26.5 \, \text{N}
\]
\[
\vec{F}_2 = 26.5 \, \text{N} - 7.6 \, \text{N}
\]
\[
\vec{F}_2 = 18.9 \, \text{N} \quad (\text{to the right})
\]

**(b) When acceleration \(a = -5.3 \, \text{m/s}^2\):**
\[
\sum \vec{F} = m \cdot a
\]
\[
7.
Transcribed Image Text:**Problem Statement:** Two horizontal forces, \(\vec{F}_1\) and \(\vec{F}_2\), are acting on a box, but only \(\vec{F}_1\) is shown in the drawing. \(\vec{F}_2\) can point either to the right or to the left. The box moves only along the x-axis. There is no friction between the box and the surface. Suppose that \(\vec{F}_1 = +7.6 \, \text{N}\) and the mass of the box is 5.0 kg. Find the magnitude and direction of \(\vec{F}_2\) when the acceleration of the box is: (a) \(+5.3 \, \text{m/s}^2\), (b) \(-5.3 \, \text{m/s}^2\), and (c) \(0 \, \text{m/s}^2\). **Diagram Explanation:** In the given diagram: - A box is shown on a flat, horizontal surface. - A force \(\vec{F}_1\) is acting on the box towards the right, indicated by a rightward arrow. **Calculations:** **(a) When acceleration \(a = +5.3 \, \text{m/s}^2\):** \[ \sum \vec{F} = m \cdot a \] \[ 7.6 \, \text{N} + \vec{F}_2 = 5.0 \, \text{kg} \times 5.3 \, \text{m/s}^2 \] \[ 7.6 \, \text{N} + \vec{F}_2 = 26.5 \, \text{N} \] \[ \vec{F}_2 = 26.5 \, \text{N} - 7.6 \, \text{N} \] \[ \vec{F}_2 = 18.9 \, \text{N} \quad (\text{to the right}) \] **(b) When acceleration \(a = -5.3 \, \text{m/s}^2\):** \[ \sum \vec{F} = m \cdot a \] \[ 7.
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