Two horizontal forces, F, and F,, are acting on a box, but only F, is shown in the drawing. F, can point either to the right or to the left. The box moves only along the x axis. There is no friction between the box and the surface. Suppose that F, = +7.6 N and the mass of the box is 5.0 kg. Find the magnitude and direction of E when the acceleration of the box is (a) +5.3 m/s?, (b) -5.3 m/s?, and (c) 0 m /s². --+x (а) Fz + v 18.9 N. (b) F2 31.8 [N (c) F, -7.6 N.
Two horizontal forces, F, and F,, are acting on a box, but only F, is shown in the drawing. F, can point either to the right or to the left. The box moves only along the x axis. There is no friction between the box and the surface. Suppose that F, = +7.6 N and the mass of the box is 5.0 kg. Find the magnitude and direction of E when the acceleration of the box is (a) +5.3 m/s?, (b) -5.3 m/s?, and (c) 0 m /s². --+x (а) Fz + v 18.9 N. (b) F2 31.8 [N (c) F, -7.6 N.
College Physics
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ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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![**Problem Statement:**
Two horizontal forces, \(\vec{F}_1\) and \(\vec{F}_2\), are acting on a box, but only \(\vec{F}_1\) is shown in the drawing. \(\vec{F}_2\) can point either to the right or to the left. The box moves only along the x-axis. There is no friction between the box and the surface. Suppose that \(\vec{F}_1 = +7.6 \, \text{N}\) and the mass of the box is 5.0 kg. Find the magnitude and direction of \(\vec{F}_2\) when the acceleration of the box is:
(a) \(+5.3 \, \text{m/s}^2\),
(b) \(-5.3 \, \text{m/s}^2\), and
(c) \(0 \, \text{m/s}^2\).
**Diagram Explanation:**
In the given diagram:
- A box is shown on a flat, horizontal surface.
- A force \(\vec{F}_1\) is acting on the box towards the right, indicated by a rightward arrow.
**Calculations:**
**(a) When acceleration \(a = +5.3 \, \text{m/s}^2\):**
\[
\sum \vec{F} = m \cdot a
\]
\[
7.6 \, \text{N} + \vec{F}_2 = 5.0 \, \text{kg} \times 5.3 \, \text{m/s}^2
\]
\[
7.6 \, \text{N} + \vec{F}_2 = 26.5 \, \text{N}
\]
\[
\vec{F}_2 = 26.5 \, \text{N} - 7.6 \, \text{N}
\]
\[
\vec{F}_2 = 18.9 \, \text{N} \quad (\text{to the right})
\]
**(b) When acceleration \(a = -5.3 \, \text{m/s}^2\):**
\[
\sum \vec{F} = m \cdot a
\]
\[
7.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fbc783430-bf94-4e65-bed2-17698c45aa9d%2F6238992d-816c-46e5-8225-830368c991dc%2Fxwrlvhn_processed.png&w=3840&q=75)
Transcribed Image Text:**Problem Statement:**
Two horizontal forces, \(\vec{F}_1\) and \(\vec{F}_2\), are acting on a box, but only \(\vec{F}_1\) is shown in the drawing. \(\vec{F}_2\) can point either to the right or to the left. The box moves only along the x-axis. There is no friction between the box and the surface. Suppose that \(\vec{F}_1 = +7.6 \, \text{N}\) and the mass of the box is 5.0 kg. Find the magnitude and direction of \(\vec{F}_2\) when the acceleration of the box is:
(a) \(+5.3 \, \text{m/s}^2\),
(b) \(-5.3 \, \text{m/s}^2\), and
(c) \(0 \, \text{m/s}^2\).
**Diagram Explanation:**
In the given diagram:
- A box is shown on a flat, horizontal surface.
- A force \(\vec{F}_1\) is acting on the box towards the right, indicated by a rightward arrow.
**Calculations:**
**(a) When acceleration \(a = +5.3 \, \text{m/s}^2\):**
\[
\sum \vec{F} = m \cdot a
\]
\[
7.6 \, \text{N} + \vec{F}_2 = 5.0 \, \text{kg} \times 5.3 \, \text{m/s}^2
\]
\[
7.6 \, \text{N} + \vec{F}_2 = 26.5 \, \text{N}
\]
\[
\vec{F}_2 = 26.5 \, \text{N} - 7.6 \, \text{N}
\]
\[
\vec{F}_2 = 18.9 \, \text{N} \quad (\text{to the right})
\]
**(b) When acceleration \(a = -5.3 \, \text{m/s}^2\):**
\[
\sum \vec{F} = m \cdot a
\]
\[
7.
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