Two helical springs, 1 and 2, are subjected to a 2 kN load as shown. Determine the maximum torsional stress produced using the simplified formula. (in MPa) E- to GPa y =0 4 2 E= 200 6Pa V = 0.3 n = 10 turn s R= 100 mm d = 20 mm n= 15 tums 75° R= IS0 Mm 250 %3D d= 16 MM %3D 2 KN www.

Two helical springs, 1 and 2, are subjected to a 2 kN load as shown. Determine the maximum torsional stress produced using the simplified formula. (in MPa) E- to GPa y =0 4 2 E= 200 6Pa V = 0.3 n = 10 turn s R= 100 mm d = 20 mm n= 15 tums 75° R= IS0 Mm 250 %3D d= 16 MM %3D 2 KN www.

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

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Concept explainers

Errors in surveying

An error in surveying is defined as the difference between two or more values of an identical quantity. However, the estimates are never accurate and there will always be a degree of variability regardless of the research tool or method used. These differences are known as errors that need to be reduced or eliminated to maintain certain levels of accuracy. Even if you carefully follow the prescribed test procedures, the considerations may contain errors.

Question

Please complete solution, no rounding off and 3 decimals for final answer.

Two helical springs, 1 and 2, are subjected to a 2 kN load as shown.
Determine the maximum torsional stress produced using the simplified
formula. (in MPa)
E= to GPa
y =0 4
E= 200 6Pa
n= 15 tums
75°
R= IS0 mm
d = 16 MM
V =0.3
n = 10 turn s
R = 100 mm
d = 20 mm
25°
2 KN

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