Two forces, of magnitudes F1 = 70.0 N and F2 = 50.0 N, act in opposite directions on a block, which sits atop a frictionless surface, as shown in the figure. (Figure 1)Initially, the center of the block is at position x; = -4.00 cm . At some later time, the block has moved to the right, and its center is at a new position, xf = 5.00 cm . Figure 1 of 1 F2 +x x=X; x=Xf

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Chapter1: Units, Trigonometry. And Vectors
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Two forces, of magnitudes F1 = 70.0 N and F2= 50.0 N , act in opposite directions on a block, which sits atop a frictionless surface, as shown in the figure. (Figure 1) Initially, the center of the block is at position xi = -4.00 cm . At some later time, the block has moved to the right, and its center is at a new position, xf = 5.00 cm .

Find:

a) the work done W1 on the block by the force of magnitude F1 = 70N as the block moves from xi = -4.00 cm to xf = 5.00 cm

b) the work done W2 on the block by the force of magnitue F2 = 50 N as the block moves from xi = -4.00 cm to xf = 5.00 cm

c) the net work done Wnet on the block by the two forces

d) the change Kf−Ki in the kinetic energy of the block as it moves from xi = -4.00 cm to xf = 5.00 cm 

Two forces, of magnitudes F1 = 70.0 N and F2 = 50.0
N, act in opposite directions on a block, which sits atop
a frictionless surface, as shown in the figure. (Figure
1)Initially, the center of the block is at position x; = -4.00
cm . At some later time, the block has moved to the right,
and its center is at a new position, xf = 5.00 cm .
Figure
1 of 1
F2
+x
x=X;
x=Xf
Transcribed Image Text:Two forces, of magnitudes F1 = 70.0 N and F2 = 50.0 N, act in opposite directions on a block, which sits atop a frictionless surface, as shown in the figure. (Figure 1)Initially, the center of the block is at position x; = -4.00 cm . At some later time, the block has moved to the right, and its center is at a new position, xf = 5.00 cm . Figure 1 of 1 F2 +x x=X; x=Xf
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