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Two forces are applied to a car in an effort to move it, as shown in the figure below. (Let F₁ = 435 N and F₂ = 368 N. Assume up and to the right are in the positive directions.) F₁ F₁ Q (a) What is the resultant vector of these two forces? magnitude N direction to the right of the forward direction (b) If the car has a mass of 3,000 kg, what acceleration does it have? Ignore friction. m/s²

Two forces are applied to a car in an effort to move it, as shown in the figure below. (Let F₁ = 435 N and F₂ = 368 N. Assume up and to the right are in the positive directions.) F₁ F₁ Q (a) What is the resultant vector of these two forces? magnitude N direction to the right of the forward direction (b) If the car has a mass of 3,000 kg, what acceleration does it have? Ignore friction. m/s²

College Physics
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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Two forces are applied to a car in an effort to move it, as shown in the figure below. (Let F₁ F 10° 30° F₁ i (a) What is the resultant vector of these two forces? magnitude N direction ° to the right of the forward direction = 435 N and F₂ = 368 N. Assume up and to the right are in the positive directions.) (b) If the car has a mass of 3,000 kg, what acceleration does it have? Ignore friction. m/s2
Transcribed Image Text:Two forces are applied to a car in an effort to move it, as shown in the figure below. (Let F₁ F 10° 30° F₁ i (a) What is the resultant vector of these two forces? magnitude N direction ° to the right of the forward direction = 435 N and F₂ = 368 N. Assume up and to the right are in the positive directions.) (b) If the car has a mass of 3,000 kg, what acceleration does it have? Ignore friction. m/s2
Expert Solution
Step 1: Given Data:

The first force F1 is: F subscript 1 equals 435 space text N end text

The second force F2 is: F subscript 2 equals 368 space text N end text

The mass of a car is: m equals 3000 space text kg end text







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