Two factories produce three different types of kitchen cutting appliances. The following table summarizes the production capacities, the numbers of each type of appliance ordered, and the daily operating costs for the factories. How many days should each factory operate to fill the orders at minimum cost? Find the minimum cost. (Use a for Houston Texas factory and y for Salem Oregon factory.) Personal Blender Family Blender Food Processor Daily Costs Minimize C= Houston Texas Factory 80/day 15/day 60/day $14,000 > 5390 Minimum cost is $ > 1575 > 4550 subject to Number of days to run Salem Oregon factory is Salem Oregon Factory 20/day 15/day 25/day $9,000 Enter the solution to the simplex matrix below. If there is no solution enter 'DNE' in the boxes below. If more than one solution exists, enter only one of the multiple solutions below. If needed round days to 1 decimal place and cost to 2 decimal places. Number of days to run the Houston Texas factory is Number Ordered 5390 1575 4550

Advanced Engineering Mathematics
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ISBN:9780470458365
Author:Erwin Kreyszig
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Chapter2: Second-order Linear Odes
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### Production Optimization Problem

Two factories produce three different types of kitchen cutting appliances. The following table summarizes the production capacities, the numbers of each type of appliance ordered, and the daily operating costs for the factories. How many days should each factory operate to fill the orders at minimum cost? Find the minimum cost.

*(Use \( x \) for Houston Texas factory and \( y \) for Salem Oregon factory.)*

|                     | Houston Texas Factory | Salem Oregon Factory | Number Ordered |
|---------------------|-----------------------|----------------------|----------------|
| **Personal Blender**| 80/day                | 20/day               | 5390           |
| **Family Blender**  | 15/day                | 15/day               | 1575           |
| **Food Processor**  | 60/day                | 25/day               | 4550           |
| **Daily Costs**     | $14,000               | $9,000               |                |

**Objective:**
Minimize \( C = \) (cost function to be determined)

**Constraints:**
- Personal Blenders: \( \geq 5390 \)
- Family Blenders: \( \geq 1575 \)
- Food Processors: \( \geq 4550 \)

**Instructions:**
Enter the solution to the simplex matrix below. If there is no solution, enter 'DNE' in the boxes below. If more than one solution exists, enter only one of the multiple solutions below. If needed, round days to 1 decimal place and cost to 2 decimal places.

- Number of days to run the Houston Texas factory is _______
- Number of days to run the Salem Oregon factory is _______
- Minimum cost is $ _______
Transcribed Image Text:### Production Optimization Problem Two factories produce three different types of kitchen cutting appliances. The following table summarizes the production capacities, the numbers of each type of appliance ordered, and the daily operating costs for the factories. How many days should each factory operate to fill the orders at minimum cost? Find the minimum cost. *(Use \( x \) for Houston Texas factory and \( y \) for Salem Oregon factory.)* | | Houston Texas Factory | Salem Oregon Factory | Number Ordered | |---------------------|-----------------------|----------------------|----------------| | **Personal Blender**| 80/day | 20/day | 5390 | | **Family Blender** | 15/day | 15/day | 1575 | | **Food Processor** | 60/day | 25/day | 4550 | | **Daily Costs** | $14,000 | $9,000 | | **Objective:** Minimize \( C = \) (cost function to be determined) **Constraints:** - Personal Blenders: \( \geq 5390 \) - Family Blenders: \( \geq 1575 \) - Food Processors: \( \geq 4550 \) **Instructions:** Enter the solution to the simplex matrix below. If there is no solution, enter 'DNE' in the boxes below. If more than one solution exists, enter only one of the multiple solutions below. If needed, round days to 1 decimal place and cost to 2 decimal places. - Number of days to run the Houston Texas factory is _______ - Number of days to run the Salem Oregon factory is _______ - Minimum cost is $ _______
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