Two electric motors​ (A and​ B) are being considered to drive a centrifugal pump. Each motor is capable of delivering 60 horsepower​ (output) to the pumping operation. It is expected that the motors will be in use 1,200 hours per year. If electricity costs ​$0.09 per​ kilowatt-hour and 1 hp​ = 0.746 ​kW, which motor should be selected if MARR​ = 7​% per​ year? Refer to the data below.

ENGR.ECONOMIC ANALYSIS
14th Edition
ISBN:9780190931919
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Chapter1: Making Economics Decisions
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Two electric motors​ (A and​ B) are being considered to drive a centrifugal pump. Each motor is capable of delivering

60

horsepower​ (output) to the pumping operation. It is expected that the motors will be in use

1,200

hours per year. If electricity costs

​$0.09

per​ kilowatt-hour and 1 hp​ =

0.746

​kW, which motor should be selected if MARR​ =

7​%

per​ year? Refer to the data below.

Two electric motors (A and B) are being considered to drive a centrifugal pump. Each motor is capable of delivering 60 horsepower (output) to the pumping operation. It is expected that the motors will be in use 1,200 hours per year. If electricity
costs $0.09 per kilowatt-hour and 1 hp = 0.746 kW, which motor should be selected if MARR
=
7% per year? Refer to the data below.
Motor B
Motor A
$1,200
0.64
$1,000
0.57
Initial Cost
Electrical Efficiency
Annual
Maintenance
Life
$50
$100
5 years
5 years
Click the icon to view the interest and annuity table for discrete compounding when the MARR is 7% per year.
The AW for Motor A is $
(Round to the nearest dollar.)
Transcribed Image Text:Two electric motors (A and B) are being considered to drive a centrifugal pump. Each motor is capable of delivering 60 horsepower (output) to the pumping operation. It is expected that the motors will be in use 1,200 hours per year. If electricity costs $0.09 per kilowatt-hour and 1 hp = 0.746 kW, which motor should be selected if MARR = 7% per year? Refer to the data below. Motor B Motor A $1,200 0.64 $1,000 0.57 Initial Cost Electrical Efficiency Annual Maintenance Life $50 $100 5 years 5 years Click the icon to view the interest and annuity table for discrete compounding when the MARR is 7% per year. The AW for Motor A is $ (Round to the nearest dollar.)
Two electric motors (A and B) are being,
costs $0.09 per kilowatt-hour and 1 hp
Click the icon to view the interest a
(Round to th
The AW for Motor A is $
More Info
N
1
2
3
4
5
68299
7
10
Single Payment
Compound
Amount
Factor
To Find F
Given P
F/P
1.0700
1.1449
1.2250
1.3108
1.4026
1.5007
1.6058
1.7182
1.8385
1.9672
Present
Worth Factor
To Find P
Given F
P/F
0.9346
0.8734
0.8163
0.7629
0.7130
0.6663
0.6227
0.5820
0.5439
0.5083
B
Discrete Compounding; i = 7%
Uniform Series
Compound
Amount
Factor
To Find F
Given A
FIA
1.0000
2.0700
3.2149
4.4399
5.7507
7.1533
8.6540
10.2598
11.9780
13.8164
Present
Worth Factor
To Find P
Given A
PIA
0.9346
1.8080
2.6243
3.3872
4.1002
4.7665
5.3893
5.9713
6.5152
7.0236
Print
Sinking
Fund
Factor
To Find A
Given F
A/F
1.0000
0.4831
0.3111
0.2252
0.1739
0.1398
0.1156
0.0975
0.0835
0.0724
Done
Capital
Recovery
Factor
To Find A
Given P
A/P
1.0700
0.5531
0.3811
0.2952
0.2439
0.2098
0.1856
0.1675
0.1535
0.1424
Uniform Gradient
Gradient
Present
Worth Factor
To Find P
Given G
P/G
0.0000
0.8734
2.5060
4.7947
7.6467
10.9784
14.7149
18.7889
23.1404
27.7156
Gradient
Uniform
Series
Factor
To Find A
Given G
A/G
0.0000
0.4831
0.9549
1.4155
1.8650
2.3032
2.7304
3.1465
3.5517
3.9461
X
use 1,200 hours per year. If electricity
Transcribed Image Text:Two electric motors (A and B) are being, costs $0.09 per kilowatt-hour and 1 hp Click the icon to view the interest a (Round to th The AW for Motor A is $ More Info N 1 2 3 4 5 68299 7 10 Single Payment Compound Amount Factor To Find F Given P F/P 1.0700 1.1449 1.2250 1.3108 1.4026 1.5007 1.6058 1.7182 1.8385 1.9672 Present Worth Factor To Find P Given F P/F 0.9346 0.8734 0.8163 0.7629 0.7130 0.6663 0.6227 0.5820 0.5439 0.5083 B Discrete Compounding; i = 7% Uniform Series Compound Amount Factor To Find F Given A FIA 1.0000 2.0700 3.2149 4.4399 5.7507 7.1533 8.6540 10.2598 11.9780 13.8164 Present Worth Factor To Find P Given A PIA 0.9346 1.8080 2.6243 3.3872 4.1002 4.7665 5.3893 5.9713 6.5152 7.0236 Print Sinking Fund Factor To Find A Given F A/F 1.0000 0.4831 0.3111 0.2252 0.1739 0.1398 0.1156 0.0975 0.0835 0.0724 Done Capital Recovery Factor To Find A Given P A/P 1.0700 0.5531 0.3811 0.2952 0.2439 0.2098 0.1856 0.1675 0.1535 0.1424 Uniform Gradient Gradient Present Worth Factor To Find P Given G P/G 0.0000 0.8734 2.5060 4.7947 7.6467 10.9784 14.7149 18.7889 23.1404 27.7156 Gradient Uniform Series Factor To Find A Given G A/G 0.0000 0.4831 0.9549 1.4155 1.8650 2.3032 2.7304 3.1465 3.5517 3.9461 X use 1,200 hours per year. If electricity
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