Two dimensional dynamics often involves solving for two unknown quantities in two separate equations describing the total force. The block in (Figure 1) has a mass m= 10 kg and is being pulled by a force F on a table with coefficient of static friction He=0.3. Four forces act on it . The applied force F (directed 0 = 30° above the horizontal). - • The force of gravity F, = mg (directly down, where g = 9.8 m/s²). - . The normal force N (directly up). . The force of static friction f. (directly left, opposing any potential motion). If we want to find the size of the force necessary to just barely overcome static friction (in which case f= N), we use the condition that the sum of the forces in both directions must be 0. Using some basic trigonometry, we can write this condition out for the forces in both the horizontal and vertical directions, respectively, as: . . F cos 0-u, N=0 Fsin 0+N-mg = 0 In order to find the magnitude of force F, we have to solve a system of two equations with both F and the normal force N unknown. Use the methods we have learned to find an expression for F in terms of m, g. 9, and μ, (no N). Express your answer in terms of m, g, 0, and μg.

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Chapter1: Units, Trigonometry. And Vectors
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How is it 29 kg.m/s ?
Sophy unt autour a ve v Dar vi DIC
unknowns.
re working on this primer, you may want to review:
• Solving a linear equation
Figure
f₁
N
F.
1 of 1
Q Type to search
F
wo
Submit
Previous Answers
Correct
Part G-Example: Finding Two Forces (Part II)
For the situation in Part F, find the magnitude of the force F (in kg- m/s²)
make the block move.
View Available Hint(s)
F = 29 kg-m/s²
Provide Feedback
3
Previous Answers
✓ Correct
Correct answer is shown. Your answer 28.94 kg m/s2 was either round
differently or used a different number of significant figures than required fo
part.
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Ne
Transcribed Image Text:Sophy unt autour a ve v Dar vi DIC unknowns. re working on this primer, you may want to review: • Solving a linear equation Figure f₁ N F. 1 of 1 Q Type to search F wo Submit Previous Answers Correct Part G-Example: Finding Two Forces (Part II) For the situation in Part F, find the magnitude of the force F (in kg- m/s²) make the block move. View Available Hint(s) F = 29 kg-m/s² Provide Feedback 3 Previous Answers ✓ Correct Correct answer is shown. Your answer 28.94 kg m/s2 was either round differently or used a different number of significant figures than required fo part. Copyright © 2024 Pearson Education Inc. All rights reserved. I Terms of Use | Privacy Policy | Permissions Contact Us I Ne
vill be
ne
of the
o review:
1 of 1
Two dimensional dynamics often involves solving for two unknown quantities in two
separate equations describing the total force. The block in (Figure 1) has a mass
m= 10 kg and is being pulled by a force F on a table with coefficient of static friction
0.3. Four forces act on it:
•
The applied force F (directed 0 = 30° above the horizontal).
• The force of gravity F,= mg (directly down, where g = = 9.8 m/s²).
.
The normal force N (directly up).
.
The force of static friction f. (directly left, opposing any potential motion).
If we want to find the size of the force necessary to just barely overcome static friction (in
which case f= N), we use the condition that the sum of the forces in both directions
must be 0. Using some basic trigonometry, we can write this condition out for the forces in
both the horizontal and vertical directions, respectively, as:
•
.
F cos 0-, N=0
Fsin 0+N-mg = 0
In order to find the magnitude of force F, we have to solve a system of two equations with
both F and the normal force N unknown. Use the methods we have learned to find an
expression for F in terms of m, g. 9. and μ, (no N).
Express your answer in terms of m, g, 0, and H.
View Available Hint(s)
F=
mg
cose + sine
Previous Answers
Correct
Transcribed Image Text:vill be ne of the o review: 1 of 1 Two dimensional dynamics often involves solving for two unknown quantities in two separate equations describing the total force. The block in (Figure 1) has a mass m= 10 kg and is being pulled by a force F on a table with coefficient of static friction 0.3. Four forces act on it: • The applied force F (directed 0 = 30° above the horizontal). • The force of gravity F,= mg (directly down, where g = = 9.8 m/s²). . The normal force N (directly up). . The force of static friction f. (directly left, opposing any potential motion). If we want to find the size of the force necessary to just barely overcome static friction (in which case f= N), we use the condition that the sum of the forces in both directions must be 0. Using some basic trigonometry, we can write this condition out for the forces in both the horizontal and vertical directions, respectively, as: • . F cos 0-, N=0 Fsin 0+N-mg = 0 In order to find the magnitude of force F, we have to solve a system of two equations with both F and the normal force N unknown. Use the methods we have learned to find an expression for F in terms of m, g. 9. and μ, (no N). Express your answer in terms of m, g, 0, and H. View Available Hint(s) F= mg cose + sine Previous Answers Correct
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