Two derivations of the identity sec¬1(-x) = # – sec-lx a. (Geometric) Here is a pictorial proof that sec-'(-x) = T - sec-lx. See if you can tell what is going on. y = sec-lx х b. (Algebraic) Derive the identity sec¬'(-x) = T – sec-lx by combining the following two equations from the text: cos(-x) = T – cosx Eq. (4), Section 1.6 sec-lx = cos'(1/x) Eq. (1)

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