**Problem Statement:** Two copper wires A and B have the same length and are connected across the same battery. If \( R_B = 5R_A \), determine the following.**(a) The ratio of their cross-sectional areas** \[\frac{A_B}{A_A} = \_\_\_\_\]**(b) The ratio of their resistivities** \[\frac{\rho_B}{\rho_A} = \_\_\_\_\]**(c) The ratio of the currents in each wire** \[\frac{I_B}{I_A} = \_\_\_\_\]This exercise asks you to analyze the relationship between resistance, cross-sectional area, resistivity, and current in copper wires connected to a battery, given that one wire has a resistance five times greater than the other.

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Two copper wires A and B have the same length and are connected across the same battery. If RR 5R , determine the following. HINT (a) the ratio of their cross-sectional areas Ав AA (b) the ratio of their resistivities PB PA (c) the ratio of the currents in each wire

Two copper wires A and B have the same length and are connected across the same battery. If RR 5R , determine the following. HINT (a) the ratio of their cross-sectional areas Ав AA (b) the ratio of their resistivities PB PA (c) the ratio of the currents in each wire

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

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Concept explainers

Microscopic view of current

In physics, the term current is expressed as the rate of flow of electric charges across the area per unit time (I=q/t). It propagates along in the direction of the motion of positive charges. When the current is caused by the motion of electrons, the direction of the current is opposite to the flow.

Question

**Problem Statement:**
Two copper wires A and B have the same length and are connected across the same battery. If \( R_B = 5R_A \), determine the following.

**(a) The ratio of their cross-sectional areas**
\[
\frac{A_B}{A_A} = \_\_\_\_
\]

**(b) The ratio of their resistivities**
\[
\frac{\rho_B}{\rho_A} = \_\_\_\_
\]

**(c) The ratio of the currents in each wire**
\[
\frac{I_B}{I_A} = \_\_\_\_
\]

This exercise asks you to analyze the relationship between resistance, cross-sectional area, resistivity, and current in copper wires connected to a battery, given that one wire has a resistance five times greater than the other.

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