Two conductor plates A and B have a voltage difference across them of 300 V. Calculate the electric field between the plates, if they are separated by a distance of 11 mm. A electron is released from plate A and accelerates to the positive plate B. Assuming the electron does not collide with anything, calculate the electron’s velocity and kinetic energy by the time it arrives at plate B. Show that the loss in potential energy is matched by the gain in kinetic energy

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A: the amount of charges on the capacitor plates, Q=CV

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A: Here is the explaination in the given image

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A: The magnetic quantum number describes the shape of the orbital.

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Electric Charges and Fields

One of the fundamental properties is the electromagnetic property. Charge cannot be destroyed by any process and this contributes formally to the law of charge conservation.