Two compounds (A and B) are reacted with iodine using a process similar to the one used in this lab. Use the data below to determine the order of the reaction with respect to compound A. [A](M) [B](M) [12] (M) Rate(M/s) 4.0 1.0 0.0050 0.000043 8.0 1.0 0.0050 0.00017

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### Determining the Order of a Reaction

#### Experiment Overview
In this experiment, two compounds (A and B) are reacted with iodine using a specific process. The provided data will be used to determine the order of the reaction with respect to compound A.

#### Data Table
The table below shows the concentration of compounds A and B, iodine, and the reaction rate.

| [A] (M) | [B] (M) | [I₂] (M) | Rate (M/s)    |
|---------|---------|----------|---------------|
| 4.0     | 1.0     | 0.0050   | 0.000043      |
| 8.0     | 1.0     | 0.0050   | 0.00017       |

#### Data Analysis
- **Concentration of Compound A ([A]):** The concentration of compound A changes from 4.0 M to 8.0 M.
- **Concentration of Compound B ([B]):** The concentration of compound B remains constant at 1.0 M.
- **Concentration of Iodine ([I₂]):** The concentration of iodine remains constant at 0.0050 M.
- **Reaction Rate (Rate):** The reaction rate changes from 0.000043 M/s to 0.00017 M/s.

With this information, the order of reaction with respect to compound A can be deduced by examining how the change in concentration of A affects the reaction rate.

#### Calculating Reaction Order
To determine the reaction order with respect to A, we use the rate law expression:
\[ \text{Rate} = k [A]^m [B]^n [I₂]^p \]

By comparing the data from the two experiments:

1. When [A] increases from 4.0 M to 8.0 M:
   \[ \frac{8.0}{4.0} = 2 \]
   
2. The corresponding change in rate:
   \[ \frac{0.00017}{0.000043} \approx 3.95 \approx 4 \]
   
   Since \( 4 \approx 2^2 \), the reaction order with respect to A is 2 (i.e., \(m = 2\)).

Therefore, the order of the reaction with respect to compound A is \(\boxed{2}\
Transcribed Image Text:### Determining the Order of a Reaction #### Experiment Overview In this experiment, two compounds (A and B) are reacted with iodine using a specific process. The provided data will be used to determine the order of the reaction with respect to compound A. #### Data Table The table below shows the concentration of compounds A and B, iodine, and the reaction rate. | [A] (M) | [B] (M) | [I₂] (M) | Rate (M/s) | |---------|---------|----------|---------------| | 4.0 | 1.0 | 0.0050 | 0.000043 | | 8.0 | 1.0 | 0.0050 | 0.00017 | #### Data Analysis - **Concentration of Compound A ([A]):** The concentration of compound A changes from 4.0 M to 8.0 M. - **Concentration of Compound B ([B]):** The concentration of compound B remains constant at 1.0 M. - **Concentration of Iodine ([I₂]):** The concentration of iodine remains constant at 0.0050 M. - **Reaction Rate (Rate):** The reaction rate changes from 0.000043 M/s to 0.00017 M/s. With this information, the order of reaction with respect to compound A can be deduced by examining how the change in concentration of A affects the reaction rate. #### Calculating Reaction Order To determine the reaction order with respect to A, we use the rate law expression: \[ \text{Rate} = k [A]^m [B]^n [I₂]^p \] By comparing the data from the two experiments: 1. When [A] increases from 4.0 M to 8.0 M: \[ \frac{8.0}{4.0} = 2 \] 2. The corresponding change in rate: \[ \frac{0.00017}{0.000043} \approx 3.95 \approx 4 \] Since \( 4 \approx 2^2 \), the reaction order with respect to A is 2 (i.e., \(m = 2\)). Therefore, the order of the reaction with respect to compound A is \(\boxed{2}\
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