Two chloride ions and two sodium ions are in water, the "effective charge" on the chloride ions (CI") is –2.00 × 10-21 c and that of the sodium ions (Na) is +2.00 x 10-21 c. (The effective charge is a way to account for the partial shielding due to nearby water molecules.) Assume that all four ions are coplanar. Na+ 30.0 Na+ o 45.0 where a = 0.250 nm, b = 0.740 nm, andc = 0.620 nm. What is the magnitude of electric force on the chloride ion in the lower right-hand corner in the diagram? IN
Two chloride ions and two sodium ions are in water, the "effective charge" on the chloride ions (CI") is –2.00 × 10-21 c and that of the sodium ions (Na) is +2.00 x 10-21 c. (The effective charge is a way to account for the partial shielding due to nearby water molecules.) Assume that all four ions are coplanar. Na+ 30.0 Na+ o 45.0 where a = 0.250 nm, b = 0.740 nm, andc = 0.620 nm. What is the magnitude of electric force on the chloride ion in the lower right-hand corner in the diagram? IN
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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Transcribed Image Text:### Required Information
Two chloride ions and two sodium ions are in water. The “effective charge” on the chloride ions (Cl⁻) is \(-2.00 \times 10^{-21}\) C, and that of the sodium ions (Na⁺) is \(+2.00 \times 10^{-21}\) C. The effective charge accounts for the partial shielding due to nearby water molecules. Assume that all four ions are coplanar.
#### Diagram Explanation
The diagram depicts four ions arranged in a coplanar configuration:
- **Chloride ions (Cl⁻):** Upper left and lower right.
- **Sodium ions (Na⁺):** Lower left and central right.
**Distances:**
- Distance \(a = 0.250\) nm is between the lower Na⁺ and Cl⁻ ions.
- Distance \(b = 0.740\) nm is between the upper Cl⁻ ion and the central Na⁺ ion.
- Distance \(c = 0.620\) nm is between the lower Na⁺ and the central Na⁺ ion.
**Angles:**
- Angle between the vector going from the central Na⁺ to the upper Cl⁻ and the positive x-axis is 30°.
- Angle between the vector from the lower Na⁺ to the central Na⁺ and the x-axis is 45°.
### Problem
What is the magnitude of the electric force on the chloride ion in the lower right-hand corner in the diagram?
\(\_\_\_\_\_\) N
This problem requires the application of Coulomb's Law to calculate the electric forces between the ions, considering their charges and separations.

Transcribed Image Text:### Required Information
Two chloride ions and two sodium ions are in water. The "effective charge" on the chloride ions (\( \text{Cl}^- \)) is \(-2.00 \times 10^{-21} \, \text{C}\) and that of the sodium ions (\( \text{Na}^+ \)) is \(+2.00 \times 10^{-21} \, \text{C}\). (The effective charge accounts for the partial shielding due to nearby water molecules.) Assume that all four ions are coplanar.
#### Diagram Explanation
- The diagram shows four ions: two \(\text{Cl}^-\) ions and two \(\text{Na}^+\) ions.
- The distances between the ions are labeled as \(a\), \(b\), and \(c\).
- \(a = 0.250 \, \text{nm}\)
- \(b = 0.740 \, \text{nm}\)
- \(c = 0.620 \, \text{nm}\)
- Angles between the vectors are shown as 30.0° and 45.0°.
#### Coordinate System
- An xy-plane is depicted to illustrate the orientation of the ions and vectors.
### Problem Statement
What is the direction of the electric force on the chloride ion in the lower right-hand corner in the diagram? Enter the angle in degrees where positive indicates above the negative x-axis and negative indicates below the positive x-axis.
\(\boxed{\,\,}\) °
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