SLONTwo charges separated by a distance r, exertan electrostatic force of magnitude Fi on eachother. When their separation is changed to rathe new force is F₂ = BF₁ where B=0.037.What is the ratio 1₂/1₁?√₂/r₁ =one på samma

Two charges separated by a distance r, exert an electrostatic force of magnitude Fi on eacr other. When their separation is changed to ra. the new force is F₂ = BF₁ where B=0.037. What is the ratio 1₂/1₁ ? √₂/r₁=

Two charges separated by a distance r, exert an electrostatic force of magnitude Fi on eacr other. When their separation is changed to ra. the new force is F₂ = BF₁ where B=0.037. What is the ratio 1₂/1₁ ? √₂/r₁=

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Question

SLON
Two charges separated by a distance r, exert
an electrostatic force of magnitude Fi on each
other. When their separation is changed to ra
the new force is F₂ = BF₁ where B=0.037.
What is the ratio 1₂/1₁?
√₂/r₁ =
one på samma

Expert Solution

Step 1

Given: The electrostatic force between the two charge with distance $r_{1}$ is $F_{1}$ .

The electrostatic force between the two charge with distance $r_{2}$ is ${βF}_{1}$ .

The value of $β$ is $0.037$ .

To determine: The ratio $\frac{r_{2}}{r_{1}}$

The expression for the force between the two charges is

$F = \frac{kqq'}{r^{2}}$

where k is the coulomb's constant, $q and q'$ are the two charges and r is the distance between the two charges.

The electrostatic force between the two charge with distance $r_{1}$ is $F_{1}$ ,

$F_{1} = \frac{kqq'}{r_{1}^{2}}$ ......................................... (1)

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