Answered: Two charges q1=3C and q2-4C Coordinate… | bartleby

Related questions

Question

100%

Two charges q1=3C and q2-4C
Coordinate of
are positioned at different coordinates as shown in the figure
q1 charge is (b, a)
and that of q2 charge is
Find the net electric field at the origin in unit vector notation .
(-b, a) .
Assume that
a=2m and b=5m . Here C denotes coulombs and
denotes meters.
A) x
component of the Electric field?
B) y
component of the Electric field?

Expert Solution

Step by step

Solved in 5 steps with 4 images

SEE SOLUTION Check out a sample Q&A here

Blurred answer

Similar questions

Please asap
Two charges lie in a line along the x axis. Charge 1 is q1 = 1.1 C and charge 2 is q2 = 2.15 C. They are each a distance of d = 0.093 m from the origin. What is the distance on the x-axis from the origin at which the electric field will be zero. Give your answer in meters.
Consider the symmetrically arranged charges in the figure, in which qa= b = -3.65 µC and qe = qd = +3.65 μC. Determine the direction of the electric field at the location of charge q. down and left up and left down and right E = Oleft down up and right up right Calculate the magnitude of the electric field E at the location of a given that the square is 5.45 cm on a side. N/C 9₂ 9c 9 9a
In the figure, the point charges are located at the corners of an equilateral triangle 21 cm on a side. Part a Find the magnitude of the electric field in N/C at the location of qa, given that qb = 8.8 μC and qc = –4.4 μC . Part b Find the direction of the electric field at qa in degrees above the negative x-axis with origin at qa. Part c What is the magnitude of the force in N on qa, given that qa = 1.7 nC? Part d What is the direction of the force on qa in degrees above the negative x-axis with origin at qa?
Find the electric field at the location of qa in the figure given that qb = qc = qd = +2.00 mC, q = -1.00 nC, and the square is 20.0 cm on a side. a) Calculare the electric field at qa due to q and qd (add the fields due to those two charges together). Give a positive value if the field is in the second quadrant, and negative if it is in the fourth quadrant. b) Now calculate the field due to qb and qc. Add the fields together, remembering that they are vectors. GIve a positive value for 2nd quadrant, negative for 4th.
Two point charges are placed on the x-axis as follows: Charge q1=+4.00nC is located 0.20m,and charge q2=+5.00nC is at x=-0.30m. a.Draw a sketch of te setting discussed in the question above. Make sure to label all points discussed. b. What are the magnitude and direction of the total force exerted by these two charges on a negative point charge q3=-6.00nC that is placed at the origin?
Q1
Referring to (Figure 1), suppose q2 is not known. Instead, it is given that q1+ q2 = -1.8 μC. Assume that the number of field lines shown precisely represents the ratio of the magnitudes of the charges. Find q1, q2, q3.
(Figure 1) shows five electric charges. Four charges with the magnitude of the charge 2.0 nC form a square with the size a = 1.5 cm . Positive charge with the magnitude of q = 2.5 nC is placed in the center of the square. What is the direction of the force on the 2.5 nC charge in the middle of the figure due to the four other charges? Express your answer in degrees to two significant figures.
Two point charges are located on a horizontal line as Shown in diagram on the right. The first small circle Represents the charge Q1 the left and small circle on right Q2 . In the middle between the two charges is point P. a) Find the net electric field due to the 2 charges at point P by finding the magnitude and direction of each one if Q1 =3μC and Q2 =5μC and distance between charges = 50 cm.