**Question:**Two charges have a force of attraction between them. If you double the distance between the charges, what happens to the force?- The force is reduced to 1/2 of its value.- The force is reduced to 1/4 of its value.- The force is doubled.- The force is four times what it was. (Highlighted)**Explanation:**This question revolves around Coulomb's Law, which describes the force of attraction or repulsion between two charged objects. According to this law, the force \( F \) between two charges is inversely proportional to the square of the distance \( r \) between them, expressed as:\[ F = k \frac{{|q_1 q_2|}}{{r^2}} \]where \( k \) is Coulomb's constant, and \( q_1 \) and \( q_2 \) are the magnitudes of the charges.If the distance \( r \) is doubled, the new force \( F' \) is:\[ F' = k \frac{{|q_1 q_2|}}{{(2r)^2}} = k \frac{{|q_1 q_2|}}{{4r^2}} = \frac{F}{4} \]Thus, the correct answer is that the force is reduced to 1/4 of its original value. The option "The force is reduced to 1/4 of its value" is correct, not "The force is four times what it was."

Given data: Two charges Attractive force between charge Original distance = r New distance (r') = 2r…

Two charges have a force of attraction between them. If you double the distance between the charges what happens to the force? The force is reduced to 1/2 of its value. The force is reduced to 1/4 of its value. The force is doubled. The force is four times what it was.

Two charges have a force of attraction between them. If you double the distance between the charges what happens to the force? The force is reduced to 1/2 of its value. The force is reduced to 1/4 of its value. The force is doubled. The force is four times what it was.

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

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