Two charges are located in the x-y plane. If q_1 = -2.90 \text{ nC} and is located at (x = 0.00 \text{ m}, y = 1.080 \text{ m}), and the second charge has magnitude of q_2 = 4.60 \text{ nC} and is located at (x = 1.40 \text{ m}, y = 0.650 \text{ m}), calculate the x and y components, E_{x} and E_{y},of the electric field, \vec{E} , in component form at the origin, (0,0) . The Coulomb force constant is 1/(4\pi \epsilon_0) = 8.99\times10^{9} \text{ N}\cdot \text{m}^{2}\text{/C}^{2}.

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Chapter1: Units, Trigonometry. And Vectors
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Two charges are located in the x-y plane. If q_1 = -2.90 \text{ nC} and is located at (x = 0.00 \text{ m}, y = 1.080 \text{ m}),
and the second charge has magnitude of q_2 = 4.60 \text{ nC} and is located at (x = 1.40 \text{ m}, y = 0.650 \text{ m}),
calculate the x and y components, E_{x} and E_{y},of the electric field, \vec{E} , in component form at the origin, (0,0) . The
Coulomb force constant is 1/(4\pi \epsilon_0) = 8.99\times10^{9} \text{ N}\cdot \text{m}^{2}\text{/C}^{2}.
33.63
N/C
-24.3
N/C
Ey
Ex
Incorrect
Incorrect
Transcribed Image Text:Two charges are located in the x-y plane. If q_1 = -2.90 \text{ nC} and is located at (x = 0.00 \text{ m}, y = 1.080 \text{ m}), and the second charge has magnitude of q_2 = 4.60 \text{ nC} and is located at (x = 1.40 \text{ m}, y = 0.650 \text{ m}), calculate the x and y components, E_{x} and E_{y},of the electric field, \vec{E} , in component form at the origin, (0,0) . The Coulomb force constant is 1/(4\pi \epsilon_0) = 8.99\times10^{9} \text{ N}\cdot \text{m}^{2}\text{/C}^{2}. 33.63 N/C -24.3 N/C Ey Ex Incorrect Incorrect
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given that,

q1=2.9 nCq1=2.9×10-9 Cat  0, 1.080mq2=4.6nCq2=4.6×10-9Cat  1.40, 0.650m

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