Two charged conducting spheres of radii a and b are connected to each other by a wire. What is the ratio of electric fields at the surfaces of the two spheres? Use the result obtained to explain why charge density on the sharp and pointed ends of a conductor is higher than on its flatter portions.
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A: Initial velocity of electron= 2.4 x 10^6 m/s E = 397 N/C
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Q: the notion useful ce from a ze of the ic field ults for x axis such that the x axis ich disk. (…
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A: We have givenElectric field strength, E=2.33×104 N/C
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- Suppose that a wire leads into another, thinner wire of the same material that has only half the cross-sectional area. In the steady state, the number of electrons per second flowing through the thick wire must be equal to the number of electrons per second flowing through the thin wire. If the electric field Ej in the thick wire is 4.3 x 102 N/C, what is the electric field E2 in the thinner wire? i N/CIn the figure below, positive charge q = 7.47 pC is spread uniformly along a thin nonconducting rod of length L = 13.0 cm. (a) What is the magnitude of the electric field produced at point P, at distance R = 6.00 cm from the rod along its perpendicular bisector? __________N/C(b) What is the direction of the field at point P?____________ ° counterclockwise from the +x-axis (please include units so that I can follow your steps easier)An electric field of 1 x 106 N/C acts on an electron, resulting in an acceleration of 1.3 x 1017 m/s2 for a short time. What is the magnitude of the radiative electric field observed at a location a distance of 3 cm away along a line perpendicular to the direction of the acceleration? i N/C
- An airplane is flying through a thundercloud at a height of 1900 m. (Flying at this height is very dangerous because of updrafts, turbulence, and the possibility of electric discharge.) If there are charge concentrations of +40.0 C at a height of 3350 m within the cloud and -40.0 C at a height of 1000 m, what is the electric field at the aircraft? (Give the magnitude and direction.) Magnitude N/CThe electron gun in a 1990’s style television tube uses a uniform electric field to accelerate electrons from rest to 5.0 × 107 m/s in a distance of 1.2 cm. What is the electric field strength?The direction of the electric field shown in each part is that produced by the charge distribution in the wire. Justify the direction shown in each part, using the Coulomb force law and the definition of E = F/q, where q is a positive test charge.
- A simple and common technique for accelerating electrons is shown in the figure below, where a uniform electric field is created between two plates. Electrons are released, usually from a hot filament, near the negative plate, and there is a small hole in the positive plate that allows the electrons to continue moving. (a) Calculate the acceleration of the electron if the field strength is 3.45 x 104 N/C. m/s² (b) Why will the electron not be pulled back to the positive plate once it moves through the hole? O The force of gravity is too strong. O There is no field outside the plates. O The other side of the positive plate also has a negative charge.You have infinitely wide grounded conducting plates that have a finite thickness as shown in the figure. 바 ut H₁ Z q origin X tH tH = We want to find the voltage V(r) in the space between the conductors. A friend proposes to use the method of images. Their idea is to put i) a negative charge -q a distance d above the bottom surface of the top plate (at z 3d) and ii) put a negative charge -q at a distance d below the top surface of the bottom plate (at z = -d). Is the potential of the image charge distribution proposed a valid solution for the original problem? Briefly justify your answer.parallel-plate capacitors are widely used in electronics such as preventing direct current leakage. An electric field is generated between a pair of plates that has a surface charge density of 7.70 x 10^-6 C/m^2 The plates are seperated by 0.49 um. a) what is the magnitude of the electric field between the plates ? b) suppose the thickness of the plates doubled, would my answer increase, decrease, or remain the same?