Two channels having the given properties shown is placed at adistance of 300 mm to back and is properly connected by a pair oflacings as shown.305 mmFy=248 mpaProperties of one channelA = 5690 mm²Ix = 67.3 x 10 mm*Assume K = 1.0-260 mm-Lucrex= 17-d = 305 mmly 2.12 x 10 mmx 17mmCIVIL ENGINEERING - STEEL DESIGNDetermine the safe axial load in kN, that the column sectioncould carry. Unsupported height of column is 6m.

Properties of one channel is givenFy = 248 MPaL = 6 m or 6000 mm

Two channels having the given properties shown is placed at a distance of 300 mm to back and is properly connected by a pair of lacings as shown. 260 mm 305 mm Fy=248 MPa Properties of one channel A=5690 mm² Ix = 67.3 x 105 mm* Assume K= 1.0 x=17- x 17mm d = 305 mm ly 2.12 x 10 mm CIVIL ENGINEERING STEEL DESIGN Determine the safe axial load in kN, that the column section could carry. Unsupported height of column is 6m.

Two channels having the given properties shown is placed at a distance of 300 mm to back and is properly connected by a pair of lacings as shown. 260 mm 305 mm Fy=248 MPa Properties of one channel A=5690 mm² Ix = 67.3 x 105 mm* Assume K= 1.0 x=17- x 17mm d = 305 mm ly 2.12 x 10 mm CIVIL ENGINEERING STEEL DESIGN Determine the safe axial load in kN, that the column section could carry. Unsupported height of column is 6m.

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

See similar textbooks

Related questions

Q: 2. The beam shown in the figure supports three concentrated loads. Determine the maximum value of P…

A: Determine maximum value of P=?

Q: AW 12 x 65 column section shown in the figure is pinned at each end and has an additional support in…

Q: What does the engineer use in a design situation?

Q: Fill in the blanks: The steel rod is stress-free before the axial loads P₁ =169 kN and P2 = 88 kN…

Q: A 76 mm x 76 mm x 6 mm angular section is welded to a gusset plate having a thickness of 10 mm as…

A: Given data: Agross=929 mm2Fy=248 MPaFu=400 MPa

Q: Use the method of the nodes to determine the force in each element of the reinforcements that are…

A: Consider the figure. Here, T is tension and C is compression.

Q: E Bars AB CD are rigid. The supports are pins at A and C and the Steel. What maximum force P can be…

A: Maximum force P

Q: : The T- beams sections shown in the figures below. f'c-28 Mpa, fy-420 Mpa. Calculate the design…

Q: Compute for the linear weight of 10 mm reinforcing bar. (Use the unit weight of the Steel). o 0.692…

A: Given data in question Diameter Steel bar To find out Linear weight Note Unit weight of steel =…

Q: 35o mm is Placed inside analuminum cylinder of Inside diameter Fomm and out side d lameter Ilomm, a…

Q: The net compression strain of steel in balanced state for the section shown in figure is most…

Q: Å W12X52 and is to cover PL = 2200KW. A fc' = fy= 248 = 20.7 column Questions: a] De termine the…

Q: The steel rod is stress-free before the axial loads P₁ =169 kN and P2 = 88 kN are applied to the…

Q: Rigid bar ABCD is loaded and supported as shown. Bars (1) and (2) are unstressed before the load P…

Q: A bronze pipe (1) is to be connected to an aluminum alloy pipe (2) at flange B. When put in place,…

A: Deformation of a structural member occurs when it is loaded, and resistance to deformation is…

Q: G K H

A: Given data:

Q: Q2/ Find (x) so that the rigid beam remains in a horizontal position. Steel L = 3m A = 500mm? E =…

Q: Determine load P such that the axial stress in the steel pipe is 200 MPa P Imm GAP RIGIO PLATE

A: It is given that :

Q: The figure below shows a shaft of three segments. It is restrained (fixed support) at both sides and…

Q: Two members, 1 and 2, are subjected to thermal stress. Determine the total deformation of member 1…

A: There will be compression stress in both bars.

Q: SkN 20KN 10KN 10kN/m 0,2*b 0,2*b 10kNm 0,8 b by 1m 3m 4m 2m 1m 2m

A: Given data: yield strength =400 MPa Factor of safety =2

Q: Consider the given figure. The bar AC is 6 mm thick and is made of a steel with a 425 MPa ultimate…

A: Given:- The thickness of the bar AC (t) = 6 mm The ultimate stress of the steel = 425 MPa The…

Q: : The T- beams sections shown in the figures below. f'c-28 Mpa, fy=420 Mpa. Calculate the design…

Q: t p= 0.2N2 in P = 500 lbf 3 1.N1 in 2p h = H -2p Material: Aluminum (E=10.0x106 Ib/in?, v= 0.3)…

A: Given N1=7 and N2=0Height of the section H=1.N1=1.7 inand thickness ρ=t=0.2N2=0.20 inreduced…

Q: Consider the truss shown in the figure. Determine the force in me members are in tension or…

A: solution Using the equilibrium equation to calculate the reaction ∑Fy=0RA+RG=150 kNTake moment about…

Q: Two members, 1 and 2, are subjected compressive force acting on the members. (in kN) Stress. AT=30…

A: Given data in question Statically indeterminate structure Diameter Side of hexagon Coefficient of…

Q: A T- beam section shown in the figure below. f'c-28 Mpa, fy-420 Mpa. Calculate the design moment…

A: Answer We are given width of flange bf = 800 mm thickness of flange tf = 100 mm thickness of web tw…

Q: Q2:If allowable stresses are at = max. value of W. W 2m 8m 165MPa, oc = 100MPa t = 70MPa determine…

Q: A fully bonded aluminum shell and steel inner Outer core bar is axially loaded. Find the normal…

Q: The lower ends of the 3 bars in the figure are at the same level before the rigid homogenous 18Mg…

A: Find the stresses developed in each bar.

Q: temperature. If the temperature in CD is reduced by 100 deg Determine the deflection of beam AB at…

Q: Q- Calculate the Poisson's ratio of the bar material if a tensile force of 350 kN is applied to it…

Q: Q1:If allowable stresses are o, 165MPa.0, 100MPa = 70MPa determine max. value of W. M 300mm 100mm Im…

Q: Calculate the strength on the Elements AB, АН, ВН, ВС, СH, CG and GH of the structure and indicate…

A: Given data in question Point loads Span member length To find out Member forces Note Used Method…

Q: The following steel circular bar (Es = 200 GPa) is divided into two segments. Segment 1 is tubular…

A: X = 6.0914mExplanation:Step 1: Step 2:

Question

Two channels having the given properties shown is placed at a
distance of 300 mm to back and is properly connected by a pair of
lacings as shown.
305 mm
Fy=248 mpa
Properties of one channel
A = 5690 mm²
Ix = 67.3 x 10 mm*
Assume K = 1.0
-260 mm-
Lucre
x= 17-
d = 305 mm
ly 2.12 x 10 mm
x 17mm
CIVIL ENGINEERING - STEEL DESIGN
Determine the safe axial load in kN, that the column section
could carry. Unsupported height of column is 6m.

Expert Solution

This question has been solved!

Explore an expertly crafted, step-by-step solution for a thorough understanding of key concepts.

SEE SOLUTION Check out a sample Q&A here

Step 1: Given

VIEW

Step 2: Calculate critical moment of inertia

VIEW

Step 3: Calculate governing slenderness ratio

VIEW

Step 4: Calculate elastic buckling stress

VIEW

Step 5: Calculate critical flexural buckling stress

VIEW

Step 6: Calculate safe axial load

VIEW

Solution

VIEW

Step by step

Solved in 7 steps with 15 images

SEE SOLUTION Check out a sample Q&A here

Knowledge Booster

Learn more about

Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, civil-engineering and related others by exploring similar questions and additional content below.

Similar questions

please help me to design a simple tensile structure for the exhibition space roof
Fill in the blanks: The steel rod is stress-free before the axial loads P₁ =169 kN and P2 = 88 kN are applied to the rod. Assuming that the walls are rigid, calculate the axial force in each segment after the loads are applied. Use E-200 GPa. A = 2000 mm² A = 900 mm² A = 1200 mm² P P₂ B C D +250 -350 mm 500 mm A -250 mm- ANSWER: KN, PBC = PCD = KN KN, PAB = (express it in whole number)
Portions of a x-in. square bar have been bent to form the two machine components shown. Knowing that the allowable stress is 18 ksi, determine the maximum load that can be applied to each component. (a) 1 in. (b) The maximum load that can be applied to component (a) is The maximum load that can be applied to component (b) is lb. lb.
SITUATION. A steel plate ABCD of thickness t = 5mm is subjected to uniform stresses: = 100 MPa 0₂ = -60 MPa. Ox E =200GPa, v= 1/3 a = 160mm and b = 200 mm Calculate the change in thickness (mm). -0.0023 mm 0.0023 mm O O 0.0045 mm - 0.0045 mm Ł B AL C D X
B2
Please show intermediate steps including free body diagrams, equations used, and problem setup so that your approach can be followed.
Hi, can somebody able to answer this one? pls. i really need it. thank you.
Tow square bars are welded together and loaded axially as shown: Determine The normal stress between A&B The normal stress between B&C The normal stress between C&D The total change in length of the bar Assume : w1 =40 mm, w2 = 50 mm, P1 = 130 kN, P2= 65 kN, and P3 =260 kN. E = 200,000 Mpa original lengths LAB = 100 mm, LBC = 120 mm, and LCD = 130 mm,
The screw clamp shown in the figure applies a P = 500 N pressing force to the wooden blocks between the jaws. In this case; a) Calculate the greatest tensile and compressive stresses occurring in the section a-a shown in the figure. b) Show the distribution of normal stresses across the section height. (draw) c) Since the clamp material has tensile strength (apull) safety = 50MPA and compression safe stress (opress) safety = 80MPA, what is the great compressive load (P) that can be applied without damaging the a-a section? %3D %3D (Please solve in detail and according to engineering rules.) Material mechanics Sectional view a-a - 20mm T. 183mm 40mm
1- Calculate maximum deflection of the beams. 2- Check the suitability of the section assuming the code limitation of L/240. 3- If maximum deflection doesn’t meet the code requirement, propose your solution. Steel: Section properties: I=366,000,000 mm4, E=2*(10)5 N/mm2
Read the question carefully and give me the right solutions with clear calculation.
For the given properties of beam below. Design the reinforcements of the beam. d'=75 mm b=400 mm d=580 mm fc'=35 MPa fy=320 MPa Mu=1000000000N mm Input is 0 in As' if compression bars are not needed. A. USE NSCP 2001, As = mm2, As' = mm2 B. USE NSCP 2015, As = mm2, As' = mm2 %3D