Two cars, both of mass m, collide and stick together. Prior to the collision, one car had been traveling north at speed 3v, while the second was traveling at speed 2v at an angle o south of east (as indicated in the figure). After the collision, the two-car system travels at speed Vfinal at an angle 0 east of north. (Figure 1)

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## Item 4: Collisions and Conservation of Momentum

### Problem Statement:
Two cars, each of mass \( m \), collide and stick together. Before the collision:
- One car was traveling north at a speed of \( 3v \).
- The second car was traveling at a speed of \( 2v \) at an angle \( \phi \) south of east (as shown in the figure).

After the collision, the two-car system travels at a speed \( v_{\text{final}} \) at an angle \( \theta \) east of north.

### Figure 1:
The figure illustrates the initial velocities and the resulting final velocity after collision:
1. The northward-traveling car (shown in blue) has a velocity vector of \( 3v \) directed straight up (north).
2. The second car (shown in yellow) traveling southeast at an angle \( \phi \) has a velocity vector labeled \( 2v \), which forms an angle \( \phi \) south of the eastward direction.
3. The combined post-collision velocity \( v_{\text{final}} \) is depicted at an angle \( \theta \) east of north.

### Calculation:
The final velocity of the system after collision can be determined using the principle of conservation of momentum. The document showcases the following inferred formula for the final velocity:

\[
v_{\text{final}} = \frac{v}{3} \sqrt{13 - 12 \sin \theta}
\]

### Submission Status:
- **Current User Attempt:** Incorrect; Try Again
- **Remaining Attempts:** 4
- **Hint Provided:** The correct answer does not depend on \( \theta \).

The equation provided seems incorrect or there might be a misunderstanding. Based on conservation of momentum principles, users need to re-evaluate their approach, ensuring accurate vector resolution and combination for both cars' velocities.
Transcribed Image Text:## Item 4: Collisions and Conservation of Momentum ### Problem Statement: Two cars, each of mass \( m \), collide and stick together. Before the collision: - One car was traveling north at a speed of \( 3v \). - The second car was traveling at a speed of \( 2v \) at an angle \( \phi \) south of east (as shown in the figure). After the collision, the two-car system travels at a speed \( v_{\text{final}} \) at an angle \( \theta \) east of north. ### Figure 1: The figure illustrates the initial velocities and the resulting final velocity after collision: 1. The northward-traveling car (shown in blue) has a velocity vector of \( 3v \) directed straight up (north). 2. The second car (shown in yellow) traveling southeast at an angle \( \phi \) has a velocity vector labeled \( 2v \), which forms an angle \( \phi \) south of the eastward direction. 3. The combined post-collision velocity \( v_{\text{final}} \) is depicted at an angle \( \theta \) east of north. ### Calculation: The final velocity of the system after collision can be determined using the principle of conservation of momentum. The document showcases the following inferred formula for the final velocity: \[ v_{\text{final}} = \frac{v}{3} \sqrt{13 - 12 \sin \theta} \] ### Submission Status: - **Current User Attempt:** Incorrect; Try Again - **Remaining Attempts:** 4 - **Hint Provided:** The correct answer does not depend on \( \theta \). The equation provided seems incorrect or there might be a misunderstanding. Based on conservation of momentum principles, users need to re-evaluate their approach, ensuring accurate vector resolution and combination for both cars' velocities.
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