Two cars are traveling on level terrain at 72 mi/h on a road with a coefficient of adhesion of 0.85. The driver of car 1 has a 2.4-s perception/reaction time and the driver of car 2 has a 2.2-s perception/reaction time. Both cars are traveling side by side and the driver able to stop their respective cars in the same distance after first seeing a roadway obstacle (perception and reaction plus vehicle stoppi distance). If the braking efficiency of car 2 is 0.75, determine the braking efficiency of car 1 (in % with 2 decimals). (Assume minimum theoretical stopping distance and ignore aerodynamic resistance.)

Two cars are traveling on level terrain at 72 mi/h on a road with a coefficient of adhesion of 0.85. The driver of car 1 has a 2.4-s perception/reaction time and the driver of car 2 has a 2.2-s perception/reaction time. Both cars are traveling side by side and the driver able to stop their respective cars in the same distance after first seeing a roadway obstacle (perception and reaction plus vehicle stoppi distance). If the braking efficiency of car 2 is 0.75, determine the braking efficiency of car 1 (in % with 2 decimals). (Assume minimum theoretical stopping distance and ignore aerodynamic resistance.)

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

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What distance will a vehicle travel before coming to a complete stop from a speed of 70 mph, (a) When the vehicle is traveling on a level roadway with no grade, (b-1) When the vehicle is traveling uphill on a roadway of constant grade = 0.10, (b-2) If the roadway grade is not constant but starts at 0.10 uphill and decreases to 0 at a continuous rate, would the braking distance be equal to, greater than, or less than that in the case of a constant 0.10 uphill grade (briefly explain why) (c) When the vehicle is traveling downhill on a roadway of constant grade = 0.10. Assume a perception-reaction time of 2.5 seconds, and an a/g value equal to 0.35.