Two cables are tied together at C and are loaded as shown. Part 1. If W=160 lb, determine the tension (a) in cable AC and (b) in cable BC. Part 2. Determine the range of values for W such that the tension will not exceed 240 lb in either cable.
Two cables are tied together at C and are loaded as shown. Part 1. If W=160 lb, determine the tension (a) in cable AC and (b) in cable BC. Part 2. Determine the range of values for W such that the tension will not exceed 240 lb in either cable.
Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
ChapterMA: Math Assessment
Section: Chapter Questions
Problem 1.1MA
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Two cables are tied together at C and are loaded as shown. Part 1. If W=160 lb, determine the tension (a) in cable AC and (b) in cable BC. Part 2. Determine the range of values for W such that the tension will not exceed 240 lb in either cable.
![The image depicts a static equilibrium problem involving a system of pulleys and weights. The setup consists of a horizontal beam with two cables, labeled AC and BC, suspended from points A and B respectively.
- **Beam Details:**
- The beam is 42 inches long in total, with a segment of 12 inches on the left from point A to point C, and a segment of 30 inches from point C to point B.
- **Cable Arrangements:**
- Cable AC is stretched diagonally downwards from point A to point C.
- Cable BC runs diagonally downwards from point B to point C.
- Both cables meet at point C, where a weight W is attached.
- **Dimensions:**
- The vertical distance from the beam to point C is 16 inches.
- The horizontal distance from point A to point C is 15 inches, and from point C to point B is 30 inches.
- There is a vertical distance of 8 inches from a point below C to where the force of 150 lb is applied downward.
- **Forces:**
- A force of 150 lb is acting downward at point W.
This setup can be analyzed using principles of static equilibrium, particularly focusing on balancing the forces in horizontal and vertical directions, and using trigonometry to resolve the tensions in cables AC and BC.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F73303aca-d795-4569-9e8f-a8984c4a41f6%2F4fd6ba77-0d06-46ee-8b9f-6cb45110d668%2Fr4d314d_processed.png&w=3840&q=75)
Transcribed Image Text:The image depicts a static equilibrium problem involving a system of pulleys and weights. The setup consists of a horizontal beam with two cables, labeled AC and BC, suspended from points A and B respectively.
- **Beam Details:**
- The beam is 42 inches long in total, with a segment of 12 inches on the left from point A to point C, and a segment of 30 inches from point C to point B.
- **Cable Arrangements:**
- Cable AC is stretched diagonally downwards from point A to point C.
- Cable BC runs diagonally downwards from point B to point C.
- Both cables meet at point C, where a weight W is attached.
- **Dimensions:**
- The vertical distance from the beam to point C is 16 inches.
- The horizontal distance from point A to point C is 15 inches, and from point C to point B is 30 inches.
- There is a vertical distance of 8 inches from a point below C to where the force of 150 lb is applied downward.
- **Forces:**
- A force of 150 lb is acting downward at point W.
This setup can be analyzed using principles of static equilibrium, particularly focusing on balancing the forces in horizontal and vertical directions, and using trigonometry to resolve the tensions in cables AC and BC.
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