Two blocks are free to slide along the frictionless wooden track as shown in the figure. The block of mass m1 = 5 kg is released from rest from the position shown, at height h = 5.00 meters above the flat part of the track. At the bottom of the track rests mass m2 = 10 kg. No work is done by non-conservative forces a.What is the speed of block m1 just as it reaches but before it collides with block m2 (use Cons. Of Energy)? b.What is the velocity of m1 just after it collides elastically with m2 (use Conservation of Momentum) and what is the velocity of m2 just after it collides elastically with m1 (use Conservation of Momentum)? c. How far back up the ramp does m1 rise after the collision (use Cons. Of Energy?) d.Find that if an 7 kg block, m3, that lies to the right of m2, is moving toward m2 (after m2’s collision with m1) at a speed of 26.8 mph (conversion!), what is the velocity of the m2/m3 couple after they collide in a perfectly inelastic collision (sticking together)
Kinematics
A machine is a device that accepts energy in some available form and utilizes it to do a type of work. Energy, work, or power has to be transferred from one mechanical part to another to run a machine. While the transfer of energy between two machine parts, those two parts experience a relative motion with each other. Studying such relative motions is termed kinematics.
Kinetic Energy and Work-Energy Theorem
In physics, work is the product of the net force in direction of the displacement and the magnitude of this displacement or it can also be defined as the energy transfer of an object when it is moved for a distance due to the forces acting on it in the direction of displacement and perpendicular to the displacement which is called the normal force. Energy is the capacity of any object doing work. The SI unit of work is joule and energy is Joule. This principle follows the second law of Newton's law of motion where the net force causes the acceleration of an object. The force of gravity which is downward force and the normal force acting on an object which is perpendicular to the object are equal in magnitude but opposite to the direction, so while determining the net force, these two components cancel out. The net force is the horizontal component of the force and in our explanation, we consider everything as frictionless surface since friction should also be calculated while called the work-energy component of the object. The two most basics of energy classification are potential energy and kinetic energy. There are various kinds of kinetic energy like chemical, mechanical, thermal, nuclear, electrical, radiant energy, and so on. The work is done when there is a change in energy and it mainly depends on the application of force and movement of the object. Let us say how much work is needed to lift a 5kg ball 5m high. Work is mathematically represented as Force ×Displacement. So it will be 5kg times the gravitational constant on earth and the distance moved by the object. Wnet=Fnet times Displacement.
Two blocks are free to slide along the frictionless wooden track as shown in the figure. The block of mass m1 = 5 kg is released from rest from the position shown, at height h = 5.00 meters above the flat part of the track. At the bottom of the track rests mass m2 = 10 kg.
No work is done by non-conservative forces
a.What is the speed of block m1 just as it reaches but before it collides with block m2 (use Cons. Of Energy)?
b.What is the velocity of m1 just after it collides elastically with m2 (use Conservation of Momentum) and what is the velocity of m2 just after it collides elastically with m1 (use Conservation of Momentum)?
c. How far back up the ramp does m1 rise after the collision (use Cons. Of Energy?)
d.Find that if an 7 kg block, m3, that lies to the right of m2, is moving toward m2 (after m2’s collision with m1) at a speed of 26.8 mph (conversion!), what is the velocity of the m2/m3 couple after they collide in a perfectly inelastic collision (sticking together)… (recall 1 in = 2.54 cm, 1 mi = 5280 ft, 1 ft = 12 in)?
Please give me slolution for part b) c) and d). I have provided the whole question for your convenience.
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