Two batteries A and B are connected in parallel; to supply a current of 160 amperes to a load resistor RL. The open-circuit terminal voltage of battery A is 123 volts and its internal resistance is 0.12 ohm. If the internal resistance of a battery B is 0.15 ohm and it delivers 90 amperes, calculate (a) the open-circuit terminal EMF of a battery B; (b) the total power taken by the load resistor RL.
Two batteries A and B are connected in parallel; to supply a current of 160 amperes to a load resistor RL. The open-circuit terminal voltage of battery A is 123 volts and its internal resistance is 0.12 ohm. If the internal resistance of a battery B is 0.15 ohm and it delivers 90 amperes, calculate (a) the open-circuit terminal EMF of a battery B; (b) the total power taken by the load resistor RL.
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
Section: Chapter Questions
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Two batteries A and B are connected in parallel; to supply a current of 160 amperes to a load resistor RL. The open-circuit terminal voltage of battery A is 123 volts and its internal resistance is 0.12 ohm. If the internal resistance of a battery B is 0.15 ohm and it delivers 90 amperes, calculate (a) the open-circuit terminal EMF of a battery B; (b) the total power taken by the load resistor RL.
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