Two balls are thrown simultaneously from the same initial height. For the first ball, the height of a ball in the air off the ground in meters, t seconds after it is thrown, is given by the equation s(t) = -4.9t2 + 12t + 10 For the second ball, its height in the air off the ground in meters, t seconds after it is thrown, is given by the equation s(t) = -4.9t² + 9t + 10 Which ball travels the highest in the air? Show your work.

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