Two 8 gram, equally charged balls are suspended on earth as shown in the diagram below. Find the charge on each ball. 20 100 100 L = 30cm L = 30cm FE 30sin10° FE r=2(30sinn0°)=10.4cm F = k =k 2
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- q 1.0 m, 0 Ꮎ Show Transcribed Text 1.0 m q Two 1.70 g positive point charges on 1.0- m-long threads repel each other after being equally charged and are held at an angle 0=16. What is the charge q?Three point charges are located as shown in the figure. q1 =-9 x 10-12 [C) and d =5 [cm] 92 =1x 10-12 (C] and d; = 1 [cm] 93 =-4 x 10-2 (C) and dy = 7 [cm] 93 d3 a. n Jami the t 1 at the- 92 INA d, d, de electri nyutuae or tne eiectrio neld created by the charge g at the origin d E What ie thadie origin. e.t harge qs at the origin. UR OL ne e E = (N/C f. JWha Oi Calculate ther THL NT Î IN/C) A charge go equal to -1.6 x 10-19 is located at the origin. The net electric field at the origin and the total force applied on the charge g will have: Osame direction Oopposite direction ik s]A charge go equal to -1.6x 10-19 is located at the origin, where the net electric field vector is supposed to be Ener "-4 i +4 ĵ IN/C). Calculate the net electric force vector created on go and select its unit (DO NOT USE THE VALUES FOUND IN THE PREVIOUS PARTS) metd -3q Q d d +9Q3 Q-3q d For the given figure only charge Q, mass of 3.0 g, can move which is initially at rest. Charges Q and Q are fixed. What is the kinetic energy of the charge Q, when it reaches the origin? (Take q = 400 uC and d= 2.3 mm) OA) 1.4 x 106 J Os 1.1 x 10+ J O c) 14 x 10s J 14 x 10 J 1.1 x 106 J