Two 50.0 mL aliquots of a sample were prepared. To one sample, a spike of 2.0 mL of 2 mg/L Fe solution was added. Samples were digested. Using after creating a set of standards, the following data was collected: • equation from the least squares fit for the calibration curve is %3D0.00072x+0.0018, where x is reported in units of ug/L and y in units of Absorbance. • Absorbance measurements for the spiked sample was 0.137; Absorbance measurement for the unspiked sample was 0.0882. Calculate the spike recovery. Report your answer as a whole number and as a % BUT DON'T TYPE IN % IN THE ANSWER BOX.

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Two 50.0 mL aliquots of a sample were prepared. To one sample, a spike of 2.0 mL of 2
mg/L Fe solution was added. Samples were digested. Using after creating a set of
standards, the following data was collected:
• equation from the least squares fit for the calibration curve is
y=0.00072x+0.0018, where x is reported in units of ug/L and y in units of
Absorbance.
• Absorbance measurements for the spiked sample was 0.137; Absorbance
measurement for the unspiked sample was 0.0882.
Calculate the spike recovery. Report your answer as a whole number and as a % BUT
DON'T TYPE IN % IN THE ANSWER BOX.
3
Transcribed Image Text:Two 50.0 mL aliquots of a sample were prepared. To one sample, a spike of 2.0 mL of 2 mg/L Fe solution was added. Samples were digested. Using after creating a set of standards, the following data was collected: • equation from the least squares fit for the calibration curve is y=0.00072x+0.0018, where x is reported in units of ug/L and y in units of Absorbance. • Absorbance measurements for the spiked sample was 0.137; Absorbance measurement for the unspiked sample was 0.0882. Calculate the spike recovery. Report your answer as a whole number and as a % BUT DON'T TYPE IN % IN THE ANSWER BOX. 3
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