Do you have any clues?? Two 50.0 mL aliquots of a sample were prepared. To one sample, a spike of 2.0 mL of 2mg/L Fe solution was added. Samples were digested. Using after creating a set ofstandards, the following data was collected:• equation from the least squares fit for the calibration curve isy=0.00072x+0.0018, where x is reported in units of ug/L and y in units ofAbsorbance.• Absorbance measurements for the spiked sample was 0.137; Absorbancemeasurement for the unspiked sample was 0.0882.Calculate the spike recovery. Report your answer as a whole number and as a % BUTDON'T TYPE IN % IN THE ANSWER BOX.3

In the least square fit equation, y = Absorbance x = Concentration of the sample

Two 50.0 mL aliquots of a sample were prepared. To one sample, a spike of 2.0 mL of 2 mg/L Fe solution was added. Samples were digested. Using after creating a set of standards, the following data was collected: • equation from the least squares fit for the calibration curve is %3D0.00072x+0.0018, where x is reported in units of ug/L and y in units of Absorbance. • Absorbance measurements for the spiked sample was 0.137; Absorbance measurement for the unspiked sample was 0.0882. Calculate the spike recovery. Report your answer as a whole number and as a % BUT DON'T TYPE IN % IN THE ANSWER BOX.