please help me with all 3 parts of this question! ### Problem DescriptionTwo 28.0 cm focal-length converging lenses are placed 16.5 cm apart. An object is placed 38.0 cm in front of one lens.### Question A:**Where will the final image formed by the second lens be located?**Input box labeled \( d_{i2} = \) cm beyond the second lens.Interactive tools for input include options for input formatting, undo, redo, and a help section."Submit" button is present for submitting the answer, along with a "Request Answer" option.### Question B:**What is the total magnification?**Input box labeled \( m = \).Interactive tools are similar to those in Question A and include options for input formatting, undo, redo, and a help section.The section is collapsible/expandable, indicated by "Part B." ### Refraction of Light Through Different Mediums#### Background InformationA light beam strikes a 2.3 cm-thick piece of plastic with a refractive index of 1.62 at a 45° angle. Below this plastic, there is a 2.8 cm-thick piece of glass with a refractive index (\(n\)) of 1.47.#### Diagram Explanation- **Diagram Overview**: The figure depicts a light beam traveling through two layers of different materials. The top layer is a plastic with a refractive index of \(n_1 = 1.62\), and the bottom layer is glass with a refractive index of \(n_2 = 1.47\).- **Light Path**: The light enters the plastic at a 45° angle and bends due to the change in medium. After traveling through the plastic, it enters the glass and bends again.- **Unknown Variable**: The diagram asks for the calculation of distance \(D\), which represents the lateral shift of the light beam as it passes through the glass.#### Problem Statement**Part A**- **Objective**: Determine the distance \(D\) as shown in the figure.- **Instruction**: Express your answer using two significant figures and include the appropriate units.#### Answer Input- **Answer Box**: Users are prompted to input their calculated value of \(D\) along with its units in separate fields labeled "Value" and "Units."### Interaction Options- **Submit**: Click to submit the answer.- **Request Answer**: Option to ask for further explanation or hints if needed.- **Feedback**: Provide feedback on the problem or the solution interface.This section is designed to educate users on the principles of refraction, Snell's Law, and the calculation of lateral shifts in light paths through different mediums.

Given data The focal length of each lens is f = 28 cm The distance between the lenses is d = 16.5…

Two 28.0 -cm -focal-length converging lenses are placed 16.5 cm apart. An object is placed 38.0 cm in front of one lens. Where will the final image formed by the second lens be located? d;2 = cm beyond the second lens Submit Request Answer • Part B What is the total magnification? Πνα ΑΣφ m =

Two 28.0 -cm -focal-length converging lenses are placed 16.5 cm apart. An object is placed 38.0 cm in front of one lens. Where will the final image formed by the second lens be located? d;2 = cm beyond the second lens Submit Request Answer • Part B What is the total magnification? Πνα ΑΣφ m =

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

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Question

please help me with all 3 parts of this question!

### Refraction of Light Through Different Mediums

#### Background Information
A light beam strikes a 2.3 cm-thick piece of plastic with a refractive index of 1.62 at a 45° angle. Below this plastic, there is a 2.8 cm-thick piece of glass with a refractive index (\(n\)) of 1.47.

#### Diagram Explanation
- **Diagram Overview**: The figure depicts a light beam traveling through two layers of different materials. The top layer is a plastic with a refractive index of \(n_1 = 1.62\), and the bottom layer is glass with a refractive index of \(n_2 = 1.47\).
- **Light Path**: The light enters the plastic at a 45° angle and bends due to the change in medium. After traveling through the plastic, it enters the glass and bends again.
- **Unknown Variable**: The diagram asks for the calculation of distance \(D\), which represents the lateral shift of the light beam as it passes through the glass.

#### Problem Statement
**Part A**
- **Objective**: Determine the distance \(D\) as shown in the figure.
- **Instruction**: Express your answer using two significant figures and include the appropriate units.

#### Answer Input
- **Answer Box**: Users are prompted to input their calculated value of \(D\) along with its units in separate fields labeled "Value" and "Units."

### Interaction Options
- **Submit**: Click to submit the answer.
- **Request Answer**: Option to ask for further explanation or hints if needed.
- **Feedback**: Provide feedback on the problem or the solution interface.

This section is designed to educate users on the principles of refraction, Snell's Law, and the calculation of lateral shifts in light paths through different mediums.

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