Two 28.0 -cm -focal-length converging lenses are placed 16.0 cm apart. An object is placed 38.0 cm in front of one lens. Part A Where will the final image formed by the second lens be located? Vo AEO ? di2 = cm beyond the second lens Submit Request Answer Part B What is the total magnification? m = Submit Reguest Answer
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- All problems involve a concave (converging) mirror that has a radius of curvature of 18.0 m.For problems 1-4, an object of height 12.0 cm is placed 15.00 m in front of the mirror. Calculate the image distance, the image height, and the magnification(not necessarily in that order). 1) Calculate di. 2) Calculate hi. 3) Calculate the magnification m. 4) Where is the image formed? A) on the object side of the optic B) on the side of the optic opposite the object C) there is no image formedA convex lens produces a real, inverted image of an object that is magnified 2.5 times when the object is 20 cm from the lens. a) What is the image distance of the lens? di = b) What is the focal length of the lens? f =Please asap
- A photographic slide is to the left of a lens. The lens projects an image of the slide onto a wall 5.95 m to the right of the slide. The image is 78.0 times the size of the slide. Part A How far is the slide from the lens? Express your answer in meters. S = Submit Part B Is the image erect or inverted? erect inverted Submit VO ΑΣΦ Part C Submit Request Answer Part D What is the focal length of the lens? Express your answer in meters. Request Answer V ΑΣΦ Request Answer Is the lens converging or diverging? converging diverging ? m mAn illuminated slide is held 48 cm from a screen. How far from the slide (between the slide and the screen) must a lens of focal length 6.5 cm be placed to form an image of the slide's picture on the screen? (Give the smaller of the two possible answers.) Number i UnitsTrue statements for optics Which of the following statements for single optic devices are true? Choose all that apply. It turns out that convex lenses always have a positive focal length. For real images, the image distance is negative and the object distance is positive. By convention, an inverted image has a positive image height. A magnification of -2 means the image is magnified. 0 Experiments have shown that converging optics can create virtual images. If an image has a magnification of -8, then the image is virtual. Which must be true? Using a single optic, an image with a negative image height is created. As a result, which of the following MUST be true? Choose all that apply. The image is real The image is virtual The image is inverted The image is upright The image distance is positive The image distance is negative The image has a positive magnification The image has a negative magnification The optic is converging The optic is diverging The optic has a positive focal length…
- Help on three part question on convex images please and thank you.Part A How far from a 51.0 mm focal-length lens must an object be placed if its image is to be magnified 2.60× and be real? do = = Submit Part B do = ΑΣΦ What if the image is to be virtual and magnified 2.60×? Submit Request Answer VE ΑΣΦ Request Answer ? ? mm mm(Figure 1) shows an object and its image formed by a thin lens. Assume that L = 16.2 cm and y = 3.45 mm. Figure Image Object 6.00 cm L 1 of 1 Optic axis Lens Part A What is the focal length of the lens? Express your answer in centimeters. - ΑΣΦ f = Submit Part B What type of lens is it? Submit Request Answer converging diverging Part C II Request Answer What is the height of the image? Express your answer in millimeters. Π ΑΣΦ = ? ? cm mm
- A concave mirror produces a virtual image that is three times as tall as the object. Part A If the object is 12 cm in front of the mirror, what is the image distance? Express your answer using two significant figures. ΑΣφ ? di = cm Submit Request Answer Part B What is the focal length of this mirror? Express your answer using two significant figures. nν ΑΣφ ? cm Submit Request AnswerNeeds Complete typed solution with 100 % accuracy.A-6.10-D lens is held 14.5 cm from an ant 1.00 mm high. Part A What is the position of the image? on the opposite side of the lens relative to the object on the same side of the lens with the object no image is formed Previous Answers ✓ Correct Part B Find the image distance. Follow the sign conventions. Express your answer to three significant figures and include the appropriate units. di = -7.69x10-² m Previous Answers ✓ Correct P Pearson Copyright © 2022 Pearson Education Inc. All rights reserved. | Terms of Use | Privacy Policy | Permissions | Contact Us | MacBook Air