Two 20.0 g ice cubes at -12.0 °C are placed into 255 g of water at 25.0 °C. Assuming no energy is transferred to or from the surroundings, calculate the final temperature, Tr, of the water after all the ice melts. heat capacity of H, O(s) 37.7 J/(mol-K) °C T = heat capacity of H, O(1) 75.3 J/(mol-K) enthalpy of fusion of H,O 6.01 kJ/mol

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Chapter1: Chemical Foundations
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General Chemistry 4th Edition
McQuarrie Rock Gallogly
BUniversity Science Books
presented by Macmillan Learning
Two 20.0 g ice cubes at-12.0 °C are placed into 255 g of water at 25.0 °C. Assuming no energy is transferred to or from the
surroundings, calculate the final temperature, Tr, of the water after all the ice melts.
heat capacity of H,0(s)
37.7 J/(mol-K)
T =
heat capacity of H,0(1)
75.3 J/(mol-K)
enthalpy of fusion of H, O
6.01 kJ/mol
Transcribed Image Text:General Chemistry 4th Edition McQuarrie Rock Gallogly BUniversity Science Books presented by Macmillan Learning Two 20.0 g ice cubes at-12.0 °C are placed into 255 g of water at 25.0 °C. Assuming no energy is transferred to or from the surroundings, calculate the final temperature, Tr, of the water after all the ice melts. heat capacity of H,0(s) 37.7 J/(mol-K) T = heat capacity of H,0(1) 75.3 J/(mol-K) enthalpy of fusion of H, O 6.01 kJ/mol
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Heat energy is that the live of the full internal energy of a system. This includes the full mechanical energy of the system and also the P.E. of the molecules.
It has been seen that the interior energy of a system may be modified by either activity heat to that, or doing work on that.
The internal energy of a system is found to extend with the rise in temperature. This increase in internal energy depends on the temperature distinction, the number of matter, etc.
Heat capability is outlined because the quantity of warmth energy needed to boost the temperature of a given amount of matter by one C.

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