Two 20.0 g ice cubes at −10.0 ∘C are placed into 285 g of water at 25.0 ∘C. Assuming no energy is transferred to or from the surroundings, calculate the final temperature, ?f, of the water after all the ice melts.
Two 20.0 g ice cubes at −10.0 ∘C are placed into 285 g of water at 25.0 ∘C. Assuming no energy is transferred to or from the surroundings, calculate the final temperature, ?f, of the water after all the ice melts.
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Two 20.0 g ice cubes at −10.0 ∘C are placed into 285 g of water at 25.0 ∘C. Assuming no energy is transferred to or from the surroundings, calculate the final temperature, ?f, of the water after all the ice melts.
Expert Solution
Step 1
Given that,
Mass of two ice cubes, mi = 2×20 g = 40 g
Initial temperature of ice, Ti, i = -10°C
Heat capacity of ice, ci = 2.09 J/g.°C
Final temperature, Tf = to be calculated
Change in temperature of ice, ∆Ti = Tf - Ti, i
= Tf - (-10°C) = Tf + 10°C
Mass of water, mw = 285.0 g
Initial temperature of water, Ti, w = 25°C
Heat capacity of water, cw = 4.184 J/g.°C
Change in temperature of water ∆Tw = Tf - Ti, w = Tf - 25°C
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