Two 1.0 (g) balls are connected by a 2.0 (cm) long insulating rod of negligible mass. One ball has a charge of +10 (nC), the other a charge of -10 (nC). The rod is held in a 1.0 × 104 (N/C) uniform electric field at an angle of 30° with respect to the field, then released. What is its initial angular acceleration? Consider I = 2.0 × 10-7 (kg m?).

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### Physics Problem: Angular Acceleration of Charged Balls in an Electric Field

#### Problem Statement:
Two 1.0 gram (g) balls are connected by a 2.0 centimeter (cm) long insulating rod of negligible mass. One ball has a charge of +10 nanocoulombs (nC), and the other has a charge of -10 nanocoulombs (nC). The rod is held in a uniform electric field of \(1.0 \times 10^4 \text{ N/C}\) at an angle of \(30^\circ\) with respect to the field and then released. Determine the rod's initial angular acceleration. The moment of inertia (I) of the system is given as \(2.0 \times 10^{-7} \text{ kg m}^2\).

#### Explanation:

1. **Mass and Charges**: 
   - **Mass of each ball**: 1.0 gram (g), which is equivalent to \(1.0 \times 10^{-3}\) kilograms (kg).
   - **Charge of one ball**: +10 nanocoulombs (nC) which is \(+10 \times 10^{-9}\) coulombs (C).
   - **Charge of the other ball**: -10 nanocoulombs (nC) which is \(-10 \times 10^{-9}\) coulombs (C).

2. **Rod Length**:
   - **Distance between the two balls**: 2.0 centimeters (cm), which is 0.02 meters (m).

3. **Electric Field**:
   - **Magnitude**: \(1.0 \times 10^4 \text{ N/C}\)
   - **Angle with respect to the field**: \(30^\circ\)

4. **Moment of Inertia (I)**: 
   - \(2.0 \times 10^{-7} \text{ kg m}^2\)

#### Objective:
   - Calculate the initial angular acceleration of the system once it is released.

#### Solution Strategy:
1. **Torque Calculation**:
   - The force on each charge due to the electric field can be calculated using \( \mathbf{F} = q \mathbf{E} \).
   - For the +10 nC charge: \( F_{+} = ( +10 \times 10^{-9} \text{
Transcribed Image Text:### Physics Problem: Angular Acceleration of Charged Balls in an Electric Field #### Problem Statement: Two 1.0 gram (g) balls are connected by a 2.0 centimeter (cm) long insulating rod of negligible mass. One ball has a charge of +10 nanocoulombs (nC), and the other has a charge of -10 nanocoulombs (nC). The rod is held in a uniform electric field of \(1.0 \times 10^4 \text{ N/C}\) at an angle of \(30^\circ\) with respect to the field and then released. Determine the rod's initial angular acceleration. The moment of inertia (I) of the system is given as \(2.0 \times 10^{-7} \text{ kg m}^2\). #### Explanation: 1. **Mass and Charges**: - **Mass of each ball**: 1.0 gram (g), which is equivalent to \(1.0 \times 10^{-3}\) kilograms (kg). - **Charge of one ball**: +10 nanocoulombs (nC) which is \(+10 \times 10^{-9}\) coulombs (C). - **Charge of the other ball**: -10 nanocoulombs (nC) which is \(-10 \times 10^{-9}\) coulombs (C). 2. **Rod Length**: - **Distance between the two balls**: 2.0 centimeters (cm), which is 0.02 meters (m). 3. **Electric Field**: - **Magnitude**: \(1.0 \times 10^4 \text{ N/C}\) - **Angle with respect to the field**: \(30^\circ\) 4. **Moment of Inertia (I)**: - \(2.0 \times 10^{-7} \text{ kg m}^2\) #### Objective: - Calculate the initial angular acceleration of the system once it is released. #### Solution Strategy: 1. **Torque Calculation**: - The force on each charge due to the electric field can be calculated using \( \mathbf{F} = q \mathbf{E} \). - For the +10 nC charge: \( F_{+} = ( +10 \times 10^{-9} \text{
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