Twelve different video games showing substance use were observed and the duration of times of game play (in seconds) are listed below. The design of the study justifies the assumption that the sample can be treated as a simple random sample. Use the sample data to construct an 80% confidence interval estimate of o, the standard deviation of the duration times of game play Assume that this sample was obtained from a population with a normal distribution 4.217 4,268 3,944 4,735 3,812 4,513 4,222 4,481 Click the icon to view the table of Chi-Square critical values 4,034 4,045 The confidence interval estimate is seces (Round to one decimal place as needed.) 3.876 4,703
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- In a test of the effectiveness of garlic for lowering cholesterol, 42 subjects were treated with garlic in a processed tablet form. Cholesterol levels were measured before and after the treatment. The changes (before - after) in their levels of LDL cholesterol (in mg/dL) have a mean of 4.1 and a standard deviation of 19.1. Construct a 99% confidence interval estimate of the mean net change in LDL cholesterol after the garlic treatment. What does the confidence interval suggest about the effectiveness of garlic in reducing LDL cholesterol? Click here to view at distribution table. Click here to view page 1 of the standard normal distribution table. Click here to view page 2 of the standard normal distribution table. What is the confidence interval estimate of the population mean u? O mg/dL < µAn investigation was carried out to study possible consequences of the high incidence of head injuries among soccer players. Three groups of college students (soccer athletes, nonsoccer athletes, and a control group consisting of students who did not participate in intercollegiate sports) were considered in the study. The following table gives information on scores from the Hopkins Verbal Learning Test (which measures immediate memory recall). In addition X = 30.1140. Sample size Sample mean score Sample standard deviation Soccer Athletes 87 30.90 3.93 Nonsoccer Athletes 96 29.94 5.34 Control 52 29.12 3.58 Suppose that it is reasonable to regard these three samples as random samples from the three student populations of interest. Is there sufficient evidence to conclude that the means for Hopkins score are not the same for the three student populations? Use α = 0.05. (Round your answer to two decimal places.) F = Use technology to find the P-value. (Round your answer to four decimal…According to a research study, college students spent 24.2 hours doing homework per week last year, on average. A random sample of 16 college students was surveyed and the mean amount of time per week each college student spent on homework was 23.7. This data has a sample standard deviation of 2.2. (Assume that the scores are normally distributed.) Researchers conduct a one-mean hypothesis at the 1% significance level, to test if the mean amount of time college students spend on homework per week is less than the mean amount of time last year. Which answer choice shows the correct null and alternative hypotheses for this test? Select the correct answer below: H0:μ=24.2; Ha:μ>24.2, which is a right-tailed test. H0:μ=24.2; Ha:μ<24.2, which is a left-tailed test. H0:μ=23.7; Ha:μ>23.7, which is a right-tailed test. H0:μ=23.7; Ha:μ<23.7, which is a left-tailed test.Two groups were selected for an experiment. The sample data is reported: Group A Group B Sample Mean Spending/day ($) 170 150 Sample Standard deviation ($) 10 5 # of Females 9 7 Sample Size 36 42 a. Set up a 99% confidence interval for the mean difference in spending between the two groups. b. At the 10% level test the alternate hypothesis that group B has lower spending level than Group A.In a test of the effectiveness of garlic for lowering cholesterol, 42 subjects were treated with garlic in a processed tablet form. Cholesterol levels were measured before and after the treatment. The changes (before - after) in their levels of LDL cholesterol (in mg/dL) have a mean of 3.9 and a standard deviation of 15.3. Construct a 99% confidence interval estimate of the mean net change in LDL cholesterol after the garlic treatment. What does the confidence interval suggest about the effectiveness of garlic in reducing LDL cholesterol? Click here to view at distribution table. Click here to view page 1 of the standard normal distribution table. Click here to view page 2 of the standard normal distribution table. What is the confidence interval estimate of the population mean u? | mg/dL < µ31 packages are randomly selected from packages received by a parcel service. The sample has a mean weight of 15.6 pounds. Assume that stdv = 2.2 pounds. What is the 95% confidence interval for the true mean weight, u, of all packages received by the parcel service?A college entrance exam company determined that a score of 24 on the mathematics portion of the exam suggests that a student is ready for college-level mathematics. To achieve this goal, the company recommends that students take a core curriculum of math courses in high school. Suppose a random sample of 150 students who completed this core set of courses results in a mean math score of 24.3 on the college entrance exam with a standard deviation of 3.2. Do these results suggest that students who complete the core curriculum are ready for college-level mathematics? That is, are they scoring above 24 on the math portion of the exam? Complete parts a) through d) below. a) State the appropriate null and alternative hypotheses. Fill in the correct answers below. The appropriate null and alternative hypotheses are Ho versus H,: ▼ Enter your answer in the edit fields and then click Check Answer. Clear All Check Answer parts 4 remaining MacBook Alir DD 111 80 888 7 FS F4 esc F2 F3 F1 $ delet @…A clinical researcher performs a clinical trial on 12 patients to determine whether a drug treatment has an effect on serum glucose. The sample mean glucose of the patients before and after the treatment are summarized in the following table. The sample standard deviation of the differences was 6. Sample mean glucose (mg/dL) Before treatment 114 After treatment 108 What type of hypothesis test should be performed?Select: Left-tailed z-test Unpaired t-test Two-tailed z-test Paired t-test What is the test statistic? What is the number of degrees of freedom? Does sufficient evidence exist to support the claim that the drug treatment has an effect on serum glucose at the α=0.05 significance level? Select: _____Yes OR _____NoA company that manufactures baseball bats believes that its new bat will allow players to hit the ball 30 feet farther than its current model. The owner hires a professional baseball player known for hitting home runs to hit ten balls with each bat and he measures the distance each ball is hit to test the company's claim. The results of the batting experiment are shown in the following table. Construct a 90 % confidence interval for the true difference between the mean distance hit with the new model and the mean distance hit with the older model. Assume that the variances of the two populations are the same. Let Population 1 be the distances of balls hit with the new model baseball bat and Population 2 be the distances of balls hit with the old model. Round the endpoints of the interval to one decimal place, if necessary. Hitting Distance (in Feet) New Model Old Model 215 234 202 298 224 294 211 246 215 268 248 211 255 226 228 284 247 221 214 259Dr. Graham is interested in determining if middle-aged adults use text messaging more or less frequently than the general population. Dr. Graham collects information on text messaging from a random sample of 50 adults ages 25 to 44. Dr. Graham finds that these individuals send or receive an average of 68 text messages per day. Using the population mean (and standard deviation) of 41.5 texts per day (34 texts per day), determine whether adults in this age group use text messaging more than the general public.In a test of the effectiveness of garlic for lowering cholesterol, 42 subjects were treated with garlic in a processed tablet form. Cholesterol levels were measured before and after the treatment. The changes (before - after) in their levels of LDL cholesterol (in mg/dL) have a mean of 4.1 and a standard deviation of 19.1. Construct a 99% confidence interval estimate of the mean net change in LDL cholesterol after the garlic treatment. What does the confidence interval suggest about the effectiveness of garlic in reducing LDL cholesterol? Click here to view at distribution table. Click here to view page 1 of the standard normal distribution table, Click here to view page 2 of the standard normal distribution table. What is the confidence interval estimate of the population mean u? mg/dL < µA company that manufactures baseball bats believes that its new bat will allow players to hit the ball 30 feet farther than its current model. The owner hires a professional baseball player known for hitting home runs to hit ten balls with each bat and he measures the distance each ball is hit to test the company's claim. The results of the batting experiment are shown in the following table. Construct a 90 % confidence interval for the true difference between the mean distance hit with the new model and the mean distance hit with the older model. Assume that the variances of the two populations are the same. Let Population 1 be the distances of balls hit with the new model baseball bat and Population 2 be the distances of balls hit with the old model. Round the endpoints of the interval to one decimal place, if necessary. Hitting Distance (in Feet) New Model 246 240 272 262 237 250 247 235 261 216 Old Model 293 232 299 279 239 228 256 292 272 298SEE MORE QUESTIONSRecommended textbooks for youMATLAB: An Introduction with ApplicationsStatisticsISBN:9781119256830Author:Amos GilatPublisher:John Wiley & Sons IncProbability and Statistics for Engineering and th…StatisticsISBN:9781305251809Author:Jay L. DevorePublisher:Cengage LearningStatistics for The Behavioral Sciences (MindTap C…StatisticsISBN:9781305504912Author:Frederick J Gravetter, Larry B. 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