b. What sample size would be required for the width of a 95% CI to be at most 0.03 irrespective ofthe value of p? TV advertising agencies face increasing challenges in reaching audience members because viewingTV programs via digital streaming is gaining in popularity. A poll reported that 80% of 2367American adults surveyed said they have watched digitally streamed TV programming on some typeof device.a. Calculate and interpret a confidence interval at the 95% confidence level for the proportion of alladult Americans who watched streamed programming up to that point in time.)

(a) Obtain the 95% confidence level for the proportion of all adult Americans who watched streamed…

Answered: TV advertising agencies face increasing…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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Mental health. The General Social Survey asked the question: “For how many days during the past30 days was your mental health, which includes stress, depression, and problems with emotions, not good?”Based on responses from 1,151 US residents, the survey reported a 95% confidence interval of 3.40 to 4.24days in 2010.(a) Interpret this interval in context of the data.(b) What does “95% confident” mean? Explain in the context of the application.(c) Suppose the researchers think a 99% confidence level would be more appropriate for this interval. Willthis new interval be smaller or wider than the 95% confidence interval?(d) If a new survey were to be done with 500 Americans, do you think the standard error of the estimatebe larger, smaller, or about the same.
Listed below are the amounts of net worth in millions of the 10 wealthiest celebrities in a certain country. Construct a 90% confidence interval. What does the result tell us about the population of all the celebrities? Does the data appear to be from a normally distributed population as required? 247 208 196 173 166 161 148 148 143 143
In September 2011, Gallup surveyed 1,004 American adults and asked them whether they blamed Barack Obama a great deal, a moderate amount, not much, or not at all for U.S. economic problems. The results showed that 53% of respondents blamed Barack Obama a great deal or a moderate amount. Calculate the 99% confidence interval for the proportion of all American adults who blame Barack Obama a great deal or a moderate amount for U.S. economic problems. O (0.504, 0.556) O (0.499, 0.561) O (0.489, 0.571) O The confidence interval cannot be determined from the information given.
The dean of students at a large college is interested in learning about their opinions regarding the percentage of first-year students who should be given parking privileges in the main lot. He sends out an email survey to all students about this issue. A large number of first-year students reply but very few sophomores, juniors, and seniors reply. Based on the responses he receives, he constructs a 90% confidence interval for the true proportion of students who believe first-year students should be given parking privileges in the main lot to be (0.71, 0.79). Which of the following may have an impact on the confidence interval, but is not accounted for by the margin of error? response bias O nonresponse bias O sampling variation O undercoverage bias
Tourism is extremely important to the economy of Florida. Hotel occupancy is an often-reported measure of visitor volume and visitor activity (Orlando Sentinel, May 19, 2018). Hotel occupancy data for February in two consecutive years are as follows, current year previous year occupied rooms 1470 1458 total rooms 1750 1800 a)What is the 95% confidence interval estimate of the change in occupancy for the one-year period? b)Do you think officials will be pleased with the results? c) Using a 0.05 level of significance, test the hypothesis that there has been an increase in the proportion of rooms occupied over the one-year period.
A political scientist claims that 38% of first-year college students characterize themselves as being “moderate” or “middle of the road” as far as their political affiliation is concerned. Believing this claimed value is too high, you survey a random sample of 400 first-year college students and find that 120 characterize themselves as being “moderate” or “middle of the road.” Based on this information, what will the test statistic be? Choose the answer below that is closest to what you calculate, and try not to do a lot of rounding until you get to the very end of your calculations. 1. -0.3 2. -1.2 3. -2.6 4. -3.3 5. None of the other answer options are correct because the test statistic should be positive, not negative.
Listed below are the amounts of net worth (in millions of dollars) of the ten wealthiest celebrities in a country. Construct a 99% confidence interval. 254 199 192 169 163 158 158 158 158 158 What is the confidence interval estimate of the population mean µ?
Medical School Enrollments. A random sample of enrollments from medical schools that specialize in research and from those that are noted for primary care is listed. Find the 90% confidence interval for the difference in the means. Primary care: 783 605 427 728 546 474 371 107 442 587 293 277 662 555 527 320 Research: 474 577 605 663 783 467 670 414 813 443 565 696 692 694 277 419 884
Ten engineering schools in the US were surveyed. the sample contains 250 electrical engineers, 80 being women; 175 chemical engineers, 40 being women. Compute a 90% confidence interval for the difference between the proportions of women in these two fields of engineering. Select one: O a. (0.02, 0.16) Ob. (0.01, 0.17] O. (0.04, 0.14) O d. [0.03, 0.15]
A clothing designer creates a unisex outfit and wants to be 95% certain that it’ll fit both men and women; it was designed to fit an individual of 65 inches height. An assistant gathers the heights of random men and women walking down the street (see the attached data). Using the data, determine if the outfit will fit both men and women with 95% confidence. Need a hypothesis test included. Data Table: Women Men 63.0 71.4 65.7 69.9 65.2 73.2 65.9 69.7 60.8 70.4 62.9 66.3 69.6 78.7 67.5 69.8 63.4 73.5 63.8 68.1 63.0 68.1 63.7 76.0 66.1 68.0 61.9 69.8 63.5 71.1 68.1 68.1 60.8 76.4 65.4 66.4 65.3 72.9 64.0 67.3 64.9 64.8 61.1 70.7
A study examined parental influence on teenagers' decisions to smoke. A group of students who had never smoked were asked about their parents' attitudes to smoking. The students were questioned two years later to see if they had started smoking. The study found that, of the 287 students whose parents disapproved, 58 became smokers. Of the 48 students with lenient parents, 11 smoked. Complete parts a through c below. a) Create a 95% confidence interval for the difference between the proportion of children with lenient parents who later smoked, p1, and the proportion of children with disapproving parents who later smoked, p2. The confidence interval for p1−p2 is −0.101negative 0.101,0.1550.155. (Round to three decimal places as needed.) b) Interpret your interval in this context. Select the correct choice below and fill in the answer boxes within your choice. (Round to one decimal place as needed.) A. There is 95% confidence that the proportion of teens…
A survey collected data on attitudes toward the quality of customer service in retail stores. The survey found that 270 of the 750 American adults sampled felt that customer service is better today than it was two years ago. We wish to develop a 94% confidence interval for the proportion of American adults who feel customer service is better today than it was two years ago. What is the population? A) the 750 American adults sampled B) customer service representatives C) all American adults

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