Tutorial Exercise You are given the dollar value of a product in 2016 and the rate at which the value of the product is expected to change during the next 5 years. Write a linear equation that gives the dollar value V of the product in terms of the year t. (Let t= 0 represent 2010.) 2016 Value $3,100 Rate $400 Increase per year Step 1 Recall that the slope of the line can be interpreted as a rate of change. In this case, the value Increases as time passes and the rate of change is $400 per year. change in value (in dollars) rate of change change in time (in years) 400 400 400 Therefore, the slope m of the linear function is m = 400/1 400 Step 2 We are to let t= 0 represent 2010. In 2016 the dollar value is given to be $3,100. Therefore, V= 3,100 when t = This point on the graph of the linear function can be defined as (t₂, v₂) = (C 3,100) x.
Tutorial Exercise You are given the dollar value of a product in 2016 and the rate at which the value of the product is expected to change during the next 5 years. Write a linear equation that gives the dollar value V of the product in terms of the year t. (Let t= 0 represent 2010.) 2016 Value $3,100 Rate $400 Increase per year Step 1 Recall that the slope of the line can be interpreted as a rate of change. In this case, the value Increases as time passes and the rate of change is $400 per year. change in value (in dollars) rate of change change in time (in years) 400 400 400 Therefore, the slope m of the linear function is m = 400/1 400 Step 2 We are to let t= 0 represent 2010. In 2016 the dollar value is given to be $3,100. Therefore, V= 3,100 when t = This point on the graph of the linear function can be defined as (t₂, v₂) = (C 3,100) x.
Glencoe Algebra 1, Student Edition, 9780079039897, 0079039898, 2018
18th Edition
ISBN:9780079039897
Author:Carter
Publisher:Carter
Chapter3: Linear And Nonlinear Functions
Section3.3: Rate Of Change And Slope
Problem 19PPS
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