Tutorial Exercise Use partial fractions to find the indefinite integral. 16x1 dx Step 1 Rewrite the polynomial in the denominator as 16x¹ - 1 = (4x²)² - 12 = (4x²-1)(C -((2x)²-13)(C = (2x - 1)(2x + 1)( x² + 1) your skip a part of Jx²+1)

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