Tutorial Exercise Let f(x) = e*g(x), where g(0) = 4 and g'(0) = 3. Find f'(0). Step 1 We are given the function f(x) = e* g(x). The first step is to find the derivative f'(x). Let h(x) = e*, and note that the function f(x) is the product of the differentiable functions h(x) and g(x). Recall the product rule in terms of two differentiable functions h(x) and g(x). d dx P'(x) = h(x) [9'cx»] + g(x) [n'cx»)] To apply this rule, we first find the derivative of h(x) = e*. h(x) = e* h'(x) We now apply the product rule. P'M) = h(x) [9°x)] + g(x) (n'cx)]| f'(x) + g(x)

Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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Tutorial Exercise
Let f(x) = e*g(x), where g(0) = 4 and g'(0)
= 3. Find f'(0).
Step 1
We are given the function f(x) = e*g(x). The first step is to find the derivative f'(x). Let h(x) = e*, and note
that the function f(x) is the product of the differentiable functions h(x) and g(x).
Recall the product rule in terms of two differentiable functions h(x) and g(x).
d
= h(x).
dx
+
f"(x) = h(x) [g'(x»] + g¢x) [n'cx)]
(*), u] (x)6-
To apply this rule, we first find the derivative of h(x) = ex.
h(x) = e*
h'(x)
We now apply the product rule.
f'(x)
+
+ g(x)
Transcribed Image Text:Tutorial Exercise Let f(x) = e*g(x), where g(0) = 4 and g'(0) = 3. Find f'(0). Step 1 We are given the function f(x) = e*g(x). The first step is to find the derivative f'(x). Let h(x) = e*, and note that the function f(x) is the product of the differentiable functions h(x) and g(x). Recall the product rule in terms of two differentiable functions h(x) and g(x). d = h(x). dx + f"(x) = h(x) [g'(x»] + g¢x) [n'cx)] (*), u] (x)6- To apply this rule, we first find the derivative of h(x) = ex. h(x) = e* h'(x) We now apply the product rule. f'(x) + + g(x)
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