Tutorial Exercise In an experiment designed to measure the Earth's magnetic field using the Hall effect, a copper bar 0.495 cm thick is positioned along an east-west direction. Assume n = 8.46 x 1028 electrons/m³ and the plane of the bar is rotated to be perpendicular to the direction of B. If a current of 8.00 A in the conductor results in a Hall voltage of 4.37 x 10-¹2 v, what is the magnitude of the Earth's magnetic field at this location? Part 1 of 3 - Conceptualize From this Table of Approximate Magnetic Field Magnitudes, the magnitude of the Earth's magnetic field is about 50 µT. We expect a result with this order of magnitude. Part 2 of 3 - Categorize We will find the magnitude of the magnetic field from the equation for the Hall effect voltage. Part 3 of 3 - Analyze Hall effect voltage is given by the following. IB nát AVH Submit where I is the current, n is the volume density of electrons, B is the magnitude of the magnetic field, and t is the thickness of the copper bar. Solving for the magnitude of the magnetic field, we have nqtAV B = = = H (8.46 × 1028 e¯/m³)(1.60 × 10-1⁹ C/e-) 8.00 3.66 x 10-5T 3660000 Your response is off by a multiple of ten. T. Skip (you cannot come back) 0.00495 X A m 4.37 12 v) x 10-12
Tutorial Exercise In an experiment designed to measure the Earth's magnetic field using the Hall effect, a copper bar 0.495 cm thick is positioned along an east-west direction. Assume n = 8.46 x 1028 electrons/m³ and the plane of the bar is rotated to be perpendicular to the direction of B. If a current of 8.00 A in the conductor results in a Hall voltage of 4.37 x 10-¹2 v, what is the magnitude of the Earth's magnetic field at this location? Part 1 of 3 - Conceptualize From this Table of Approximate Magnetic Field Magnitudes, the magnitude of the Earth's magnetic field is about 50 µT. We expect a result with this order of magnitude. Part 2 of 3 - Categorize We will find the magnitude of the magnetic field from the equation for the Hall effect voltage. Part 3 of 3 - Analyze Hall effect voltage is given by the following. IB nát AVH Submit where I is the current, n is the volume density of electrons, B is the magnitude of the magnetic field, and t is the thickness of the copper bar. Solving for the magnitude of the magnetic field, we have nqtAV B = = = H (8.46 × 1028 e¯/m³)(1.60 × 10-1⁹ C/e-) 8.00 3.66 x 10-5T 3660000 Your response is off by a multiple of ten. T. Skip (you cannot come back) 0.00495 X A m 4.37 12 v) x 10-12
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Author:Raymond A. Serway, Chris Vuille
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Chapter1: Units, Trigonometry. And Vectors
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Transcribed Image Text:Tutorial Exercise
In an experiment designed to measure the Earth's magnetic field using the Hall effect, a copper bar 0.495 cm thick is positioned along an east-west
direction. Assume n = 8.46 × 1028 electrons/m³ and the plane of the bar is rotated to be perpendicular to the direction of B. If a current of 8.00 A in the
-12
conductor results in a Hall voltage of 4.37 x 10 V, what is the magnitude of the Earth's magnetic field at this location?
Part 1 of 3 - Conceptualize
From this Table of Approximate Magnetic Field Magnitudes, the magnitude of the Earth's magnetic field is about 50 μT. We expect a result with this order
of magnitude.
Part 2 of 3 - Categorize
We will find the magnitude of the magnetic field from the equation for the Hall effect voltage.
Part 3 of 3 - Analyze
Hall effect voltage is given by the following.
IB
nqt'
AVH
where I is the current, n is the volume density of electrons, B is the magnitude of the magnetic field, and t is the thickness of the copper bar. Solving for
the magnitude of the magnetic field, we have
B =
=
Need Help?
nqtAVH
I
(8.46 × 10²8 e¯/m³)(1.60 × 10-¹⁹ C/e¯
/e¯)(!
8.00
-5
3.66
x 10 T = 3660000
Your response is off by a multiple of ten. μT.
Submit Skip (you cannot come back)
Read It
0.00495
X
A
m)(
4.37
x 10-12 v)
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