Tutorial Exercise Find the equation of the line through the point (4,7) that cuts off the least area from the first quadrant. y-A= B(x-C) Part 1 of 7 A line with slope m through (4, 7) has equation y= mx + (x, y) Submit Skip (you cannot come back) (Solve for b.)

Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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4.6 Question 11

Tutorial Exercise
Find the equation of the line through the point (4, 7) that cuts off the least area from the first quadrant.
y - A = B(x - C)
Part 1 of 7
A line with slope m through (4, 7) has equation y = mx +
(x, y)
Submit Skip (you cannot come back)
(Solve for b.)
Transcribed Image Text:Tutorial Exercise Find the equation of the line through the point (4, 7) that cuts off the least area from the first quadrant. y - A = B(x - C) Part 1 of 7 A line with slope m through (4, 7) has equation y = mx + (x, y) Submit Skip (you cannot come back) (Solve for b.)
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