Tutorial Exercise Evaluate the indefinite integral as an infinite series. ex - 1 dx 12 11x Step 1 Since ex = > *" and the n = 0 term equals 1 then ex - 1 = n! n = 0 n! 1 n = Step 2 Since ex - 1 = x", then 12(e* – 1) = _12 x^ = Š 12( "-1 - E 11x n! n = 1 11x n! n = 1 n= 1 11n! Step 3 12x" 11n(11n)! 00 00 12(ex – 1) )+ c. Now we have 12x" - 1 dx = 11x 11n! n = 1 n = 1
Tutorial Exercise Evaluate the indefinite integral as an infinite series. ex - 1 dx 12 11x Step 1 Since ex = > *" and the n = 0 term equals 1 then ex - 1 = n! n = 0 n! 1 n = Step 2 Since ex - 1 = x", then 12(e* – 1) = _12 x^ = Š 12( "-1 - E 11x n! n = 1 11x n! n = 1 n= 1 11n! Step 3 12x" 11n(11n)! 00 00 12(ex – 1) )+ c. Now we have 12x" - 1 dx = 11x 11n! n = 1 n = 1
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
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
Transcribed Image Text:Tutorial Exercise
Evaluate the indefinite integral as an infinite series.
ex
- 1
12
11x
xp
Step 1
00
and the n = 0 term equals1
n!
Since ex =
then ex - 1 =
| 1
n!
1.
n = 0
Step 2
00
12 x" =
12
Since ex - 1 =
then 12(ex - 1) -.
n-1
n!
n = 1
11x
n = 1
11x
n!
n = 1
11n!
Step 3
12x - 1
dx =
12x"
11n(11n)!
12(e - 1) dx =
+ C.
Now we have
11x
11n!
n = 1
n = 1
Submit | Skip (you cannot come back)
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