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Tutorial Exercise Consider a binomial random variable with n=8 and p=0.3. Let x be the number of successes in the sample. Evaluate the probability. P(2 ≤ x ≤ 4) Step 1 A binomial experiment consists of n identical trials with probability of success p on each trial. The binomial formula that follows can be used to find the probability of exactly k successes in n trials, where q = 1 - p. P(x = k)=C₂^pkq-k= Here, we are to find P(2 ≤ x ≤ 4), which When calculating P(x = 3), k = 3✔ P(x = 2) = Step 2 We now have all the values needed to calculate the probability statements P(x=2), P(x = 3), and P(x = 4). Recall n=8, p=0.3, and q = 0.7. Calculate P(x = 2), P(x= 3), and P(x = 4), rounding the results to five decimal places. n! P(x = k) = pan-k ki(n-k)!" 81 21(8-2)! (0.3)2( 8! P(x = 3) = 31(8-3), (0.3)³( P(x = 4) = n! k!(n-k)!pg-k 8! 41(8-4)! (0.3)4( can be thought of as P(x = 2) + P(x = 3) + P(x = 4). We are given n = 8 and p = 0.3, so q = 1-p=1-0.3 = 0.7✔ 3, and when calculating P(x = 4), k= 4✔ 4 ⁰-² ⁰-⁹ ])*-* 0.7. The value of k will change with each probability statement. When calculating P(x=2), k = 2.

Tutorial Exercise Consider a binomial random variable with n=8 and p=0.3. Let x be the number of successes in the sample. Evaluate the probability. P(2 ≤ x ≤ 4) Step 1 A binomial experiment consists of n identical trials with probability of success p on each trial. The binomial formula that follows can be used to find the probability of exactly k successes in n trials, where q = 1 - p. P(x = k)=C₂^pkq-k= Here, we are to find P(2 ≤ x ≤ 4), which When calculating P(x = 3), k = 3✔ P(x = 2) = Step 2 We now have all the values needed to calculate the probability statements P(x=2), P(x = 3), and P(x = 4). Recall n=8, p=0.3, and q = 0.7. Calculate P(x = 2), P(x= 3), and P(x = 4), rounding the results to five decimal places. n! P(x = k) = pan-k ki(n-k)!" 81 21(8-2)! (0.3)2( 8! P(x = 3) = 31(8-3), (0.3)³( P(x = 4) = n! k!(n-k)!pg-k 8! 41(8-4)! (0.3)4( can be thought of as P(x = 2) + P(x = 3) + P(x = 4). We are given n = 8 and p = 0.3, so q = 1-p=1-0.3 = 0.7✔ 3, and when calculating P(x = 4), k= 4✔ 4 ⁰-² ⁰-⁹ ])*-* 0.7. The value of k will change with each probability statement. When calculating P(x=2), k = 2.

MATLAB: An Introduction with Applications
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
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Tutorial Exercise Consider a binomial random variable with n = 8 and p=0.3. Let x be the number of successes in the sample. Evaluate the probability. P(2 ≤ x ≤ 4) Step 1 A binomial experiment consists of n identical trials with probability of success p on each trial. The binomial formula that follows can be used to find the probability of exactly k successes in n trials, where q = 1 - p. P(x = k) = C₂npkqn - k Here, we are to find P(2 ≤ x ≤ 4), which can be thought of as P(x = 2) + P(x = 3) + P(x = 4). We are given n = 8 and p = 0.3, so q = 1 - p = 10.3 = 0.7 When calculating P(x = 3), k = 3 3 and when calculating P(x = 4), k = 4 P(x = k) : P(x = 2) Step 2 We now have all the values needed to calculate the probability statements P(x = 2), P(x = 3), and P(x = 4). Recall n = 8, p = 0.3, and q = 0.7. Calculate P(x = 2), P(x = 3), and P(x = 4), rounding the results to five decimal places. P(x = 3) = = P(x = 4) = = n! k! (n – k)!' n-k 8! 2!(8 — 2), (0.3)2([ n! pkqn k!(n - k)!' 8! 3!(8 - 3)! (0.3)3( [ 8! - 4!(8 — 4)! (0.3)4( [ 8-2 n-k 8-3 8-4 4 0.7 The value of k will change with each probability statement. When calculating P(x = 2), k = 2.
Transcribed Image Text:Tutorial Exercise Consider a binomial random variable with n = 8 and p=0.3. Let x be the number of successes in the sample. Evaluate the probability. P(2 ≤ x ≤ 4) Step 1 A binomial experiment consists of n identical trials with probability of success p on each trial. The binomial formula that follows can be used to find the probability of exactly k successes in n trials, where q = 1 - p. P(x = k) = C₂npkqn - k Here, we are to find P(2 ≤ x ≤ 4), which can be thought of as P(x = 2) + P(x = 3) + P(x = 4). We are given n = 8 and p = 0.3, so q = 1 - p = 10.3 = 0.7 When calculating P(x = 3), k = 3 3 and when calculating P(x = 4), k = 4 P(x = k) : P(x = 2) Step 2 We now have all the values needed to calculate the probability statements P(x = 2), P(x = 3), and P(x = 4). Recall n = 8, p = 0.3, and q = 0.7. Calculate P(x = 2), P(x = 3), and P(x = 4), rounding the results to five decimal places. P(x = 3) = = P(x = 4) = = n! k! (n – k)!' n-k 8! 2!(8 — 2), (0.3)2([ n! pkqn k!(n - k)!' 8! 3!(8 - 3)! (0.3)3( [ 8! - 4!(8 — 4)! (0.3)4( [ 8-2 n-k 8-3 8-4 4 0.7 The value of k will change with each probability statement. When calculating P(x = 2), k = 2.
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