Truss 2KN and 60 degrees
Chapter2: Loads On Structures
Section: Chapter Questions
Problem 1P
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Question
Truss 2KN and 60 degrees

Transcribed Image Text:The image contains a free body diagram drawn on graph paper. It includes a truss structure with two triangular sections labeled as A-B-E and E-C-D. Below is a detailed description and explanation:
### Diagram Components:
- **Points/Nodes:**
- A, B, C, D, E
- **Distances:**
- The horizontal span between point A and point E is 10 meters.
- The horizontal span between point E and point D is also 10 meters.
- **Loads:**
- There is a vertical load of 2 kN applied downward at point C.
- **Reactions:**
- There are vertical reaction forces at points A and D, indicated by upward arrows.
### Calculations/Annotations:
- **Equations:**
- At the top left:
```
1.73 * AD sin 60 = 0
Fx = -144.34 cos 60
```
- Subsequent calculations:
```
123
——— = 0
sin 60
```
```
-123 / 866 = 144.34 N
```
- Finally, there is a note of:
```
Ex = 72.17 N
```
### Explanation:
The diagram appears to illustrate a truss problem where a vertical load is applied, and the equilibrium equations are being used to find the reactions at the supports and possibly internal forces within the truss members. The trigonometric calculations seem related to resolving forces at different angles, with references to components and reactions in the horizontal direction.
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