Trite the charge-balance equations for a solution that is a. 0.15 M in HF. %3D b. 0.16 M in (CH3)2NH. C. saturated with Ag, CO3.

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**Charge-Balance Equations for Solutions:**

a. **0.15 M in HF**

- \[ \text{[H}^+\text{]} = \text{[F}^-\text{]} + \text{[OH}^-\text{]} \]

b. **0.16 M in (CH₃)₂NH**

- \[ \text{[CH₃)₂NH₃}^+\text{]} + \text{[OH}^-\text{]} = \text{[CH₃)₂NH]} \]

c. **Saturated with Ag₂CO₃**

- \[ 2\text{[Ag}^+\text{]} + \text{[H}^+\text{]} = \text{[CO₃}^{2-}\text{]} + \text{[HCO₃}^-\text{]} + \text{[OH}^-\text{]} \]

**Explanation:**

These equations illustrate the charge balance in different chemical solutions. 

- For HF solution, the hydrogen ions (\[\text{H}^+\]) balance with fluoride ions (\[\text{F}^-\]) and hydroxide ions (\[\text{OH}^-\]).
- In the solution of dimethylamine ((CH₃)₂NH), the positively charged ions (\[\text{(CH₃)₂NH₃}^+\]) are balanced with dimethylamine and hydroxide ions.
- For a solution saturated with silver carbonate (Ag₂CO₃), the silver ions and hydrogen ions together balance the carbonate or bicarbonate ions and hydroxide ions. The equation also accounts for potential equilibrium shifts that produce bicarbonate (\[\text{HCO₃}^-\]).
Transcribed Image Text:**Charge-Balance Equations for Solutions:** a. **0.15 M in HF** - \[ \text{[H}^+\text{]} = \text{[F}^-\text{]} + \text{[OH}^-\text{]} \] b. **0.16 M in (CH₃)₂NH** - \[ \text{[CH₃)₂NH₃}^+\text{]} + \text{[OH}^-\text{]} = \text{[CH₃)₂NH]} \] c. **Saturated with Ag₂CO₃** - \[ 2\text{[Ag}^+\text{]} + \text{[H}^+\text{]} = \text{[CO₃}^{2-}\text{]} + \text{[HCO₃}^-\text{]} + \text{[OH}^-\text{]} \] **Explanation:** These equations illustrate the charge balance in different chemical solutions. - For HF solution, the hydrogen ions (\[\text{H}^+\]) balance with fluoride ions (\[\text{F}^-\]) and hydroxide ions (\[\text{OH}^-\]). - In the solution of dimethylamine ((CH₃)₂NH), the positively charged ions (\[\text{(CH₃)₂NH₃}^+\]) are balanced with dimethylamine and hydroxide ions. - For a solution saturated with silver carbonate (Ag₂CO₃), the silver ions and hydrogen ions together balance the carbonate or bicarbonate ions and hydroxide ions. The equation also accounts for potential equilibrium shifts that produce bicarbonate (\[\text{HCO₃}^-\]).
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