Trisect a given quadrilateral by means of two straight lines drawn from (i) one of its vertices; (ii) a given point on one of its sides. CONSTRUCTION: (i) Let ABCD be the given quadrilateral. Convert ABCD into an equal DAE, through the required vertix D, by drawing CE || DB and joining DE. Trisect AE in F, G. Draw FP, GQ || DB. Hence DP, DQ are the two required lines D

Q: If RV = 8b - 23 and TV = 3b + 2, find RV in parallelogram RSTU. %3D T. U R RV %I

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