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Trigonometric Substitutions The three basic trigonometric substitutions are in the table below. Integral Contains Try using Substitution Va? – 2? Va? +22 V– a² I= a sin 0, -<0< z= asec 8, 0<8< 풀 or 풀 <8<ㅠ I= a tan 0, Part 1. Using the substitution: z = tan 0, - 5 <0< 4, re-write the indefinite integral then evaluate in terms of 0. dr = Note: type 'theta' for 0 and 'dtheta' for de. Part 2. Back substituting in the antiderivative you found in Part 1. above we have de +22 Note: answer should be in terms of r only.

Trigonometric Substitutions The three basic trigonometric substitutions are in the table below. Integral Contains Try using Substitution Va? – 2? Va? +22 V– a² I= a sin 0, -<0< z= asec 8, 0<8< 풀 or 풀 <8<ㅠ I= a tan 0, Part 1. Using the substitution: z = tan 0, - 5 <0< 4, re-write the indefinite integral then evaluate in terms of 0. dr = Note: type 'theta' for 0 and 'dtheta' for de. Part 2. Back substituting in the antiderivative you found in Part 1. above we have de +22 Note: answer should be in terms of r only.

Calculus: Early Transcendentals
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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PLEASE CIRCLE/NUMBER THE ANSWERS. WRITE IN THE SAME FORMULA. MAKE SURE PART 2, THE FORMULA IS LINEAR IN THE CONSTANT 'C' !!!! THANK YOU

Trigonometric Substitutions The three basic trigonometric substitutions are in the table below. Integral Contains Try using Substitution Va? – 2? Va? +22 V– a² I= a sin 0, -<0< z= asec 8, 0<8< 풀 or 풀 <8<ㅠ I= a tan 0, Part 1. Using the substitution: z = tan 0, - 5 <0< 4, re-write the indefinite integral then evaluate in terms of 0. dr = Note: type 'theta' for 0 and 'dtheta' for de. Part 2. Back substituting in the antiderivative you found in Part 1. above we have de +22 Note: answer should be in terms of r only.
Transcribed Image Text:Trigonometric Substitutions The three basic trigonometric substitutions are in the table below. Integral Contains Try using Substitution Va? – 2? Va? +22 V– a² I= a sin 0, -<0< z= asec 8, 0<8< 풀 or 풀 <8<ㅠ I= a tan 0, Part 1. Using the substitution: z = tan 0, - 5 <0< 4, re-write the indefinite integral then evaluate in terms of 0. dr = Note: type 'theta' for 0 and 'dtheta' for de. Part 2. Back substituting in the antiderivative you found in Part 1. above we have de +22 Note: answer should be in terms of r only.
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