Trials in an experiment with a polygraph include 97 results that include 24 cases of wrong results and 73 cases of correct results. Use a 0.05 significance level totest the claim that such polygraph results are correct less than 80% of the time. Identify the null hypothesis, alternative hypothesis, test statistic, P-value, conclusionabout the null hypothesis, and final conclusion that addresses the original claim. Use the P-value method. Use the normal distribution as an approximation of thebinomial distribution.....Let p be the population proportion of correct polygraph results. Identify the null and alternative hypotheses. Choose the correct answer below.O A. H,: p= 0.80H;: p+0.80O B. H,: p= 0.20H,: p> 0.20O C. H, p= 0.20H,: p<0.20D. H2: p= 0.80H,: p<0.80O E. H, p= 0.80H,: p> 0.80OF. H,: p= 0.20H,: p#0.20The test statistic is z=| (Round to two decimal places as needed.)

Given : Claim : The proportion of polygraph results are correct less than 80% of the time.

Answered: Trials in an experiment with a…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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A generic experiment involving peas yeilded one sample of offspring consisting of 433 green peas and 152 yellow peas. Use a 0.05 siginificance level to test the claim that under the same circumstances, 25% of offspring peas will be yellow. Identify the null hypothesis, alternative hypothesis, test statistic, P-Value, conclusion about the null hypothesis, and final conclusion that addresses the orginal claim. Use the P-Value method and the normal distribution as an approximation to the binominial distribution.
The average American consumes 86 liters of alcohol per year. Does the average college student consume more alcohol per year? A researcher surveyed 11 randomly selected college students and found that they averaged 95.8 liters of alcohol consumed per year with a standard deviation of 20 liters. What can be concluded at the the a = 0.05 level of significance? a. For this study, we should use t-test for a population mean O b. The null and alternative hypotheses would be: Ho: μ = H₁: μ > O 86 O 86 c. The test statistic (t) = d. The p-value = e. The p-value is ? a f. Based on this, we should Select an answer the null hypothesis. g. Thus, the final conclusion is that ... 1.625 (please show your answer to 3 decimal places.) (Please show your answer to 4 decimal places.) O The data suggest the population mean is not significantly more than 86 at a = 0.05, so there is statistically insignificant evidence to conclude that the population mean amount of alcohol consumed by college students is…
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Describe the difference in the conclusions that one could draw from a sample T-test when CLT did NOT kick in, as in qqnorm() did not show a normal distribution for the sample size. What could one do instead of a T-test, and what would their test statistic be?
Obtain the confidence limits for the ratio of variances of two normal populations.
The amount of water consumed each week by Bronx residences is normally distributed. The population mean of water consumption is 120.3 gallons with a standard deviation of 10.0 gallons. Test the claim at the 0.10 significance level that the average amount of water consumed is not 125 gallons with a sample size of 100 residences. Do you retain or reject the null hypothesis?
Scores on a standarized exam are known to follow a normal distribution with a standard deviation of 5. A researcher finds a random sample of 25 exam scores has a mean score of 72. Use this to find a 88% confidence interval for the mean exam score of all students taking the exam.
Small-business telephone users were surveyed 6 months after access to carriers other than Carrier A became available for wide-area telephone service. Of a random sample of 240 Carrier A users, 135 said they were attempting to learn more about their options, as did 227 of an independent random sample of 260 users of alternate carriers. Test, at the 1% significance level against a two-sided alternative, the null hypothesis that the two population proportions are the same. Click the link to view a standard normal distribution table. be the Let Px be the proportion of Carrier A users who said they were attempting to learn more about their options and Py proportion of users of alternate carriers who said they were attempting to learn more about their options. Determine the null and alternative hypotheses. Choose the correct answer below. O A. Ho: Px-Py=0 H₁: Px-Py 20 O D. Ho: Px-P₁ #0 H₁: Px - Py = 0 B. Ho: Px-Py = 0 H₁: Px-Py 0
A researcher wishes to test whether the mean of a normally distributed population is greater than 1.06 at the 5% significance level. Based upon 22 independent observations, she observes a sample mean of 1.77 and a sample standard deviation of 0.84. Determine the degrees of freedom of the null distribution of Student's t test.
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Workers' Distractions. A recent study showed that the modern working person experiences an average of 2.1 hours per day of distractions (phone calls, e- mails, impromptu visits, etc.). A random sample of 16 workers for a large corporation found that these workers were distracted an average of 1.8 hours per day and the standard deviation was 20 minutes. Estimate the true mean population distraction time with 90% confidence, and compare your answer to the results of the study. (1.654,1.946). Mean of the study is outside or "different" from the result of our study.

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