Trial 1 Trial 2 Trial 3 Trial 4 Beaker 1st cup 50mL of 50mL of Mass of empty polystyrene cup 2M HCl 2M NaOH 2M HNO 3 1M HCl 2M NaOH 2M HCl 2M NaOH 2M NaOH 13.94g 14.50g 13.76g 14.19g Mass of cup + mixture 98.53g 98.86g 98.02g 96.62g Mass of mixture 84.59g 84.36g 84.26g 82.43g Initial temp of 1st reagent (from graph) 22.1°C 22.2°C 22.6°C 22.7°C Final temp of mixture (from graph) At Temperature change Total heat evolved in reaction (AHn) Number of moles of H₂O formed 36.1°C 36.0°C 36.0°C 30.0°C 14°C 13.8°C 13.4°C 7.3°C 4.94 kJ 4.87 kJ 4.72 kJ 2.52 kJ 0.100 mol 0.100 mol 0.100 mol Limiting reagent 0.050 mol Molar heat of neutralization (AH) -49.4 -48.7 -47.2 -50.4 kJ/mol kJ/mol kJ/mol kJ/mol Molar heat of neutralization calculated from Hess's Law and data on pg 138 of lab manual Percentage difference between experimental and calculated value (%Diff) Le AH - best of neutralization raolar beat of neutralization temperature charge of solution mass of final solutice -specific heat of final solution number of moles of HCI AH CA AH -mC st AH AHA Hess's law can be used to calculate the molar heat of neutralization from literature values for bears of formation of HCI, NaOH NaCl and HO. These values and the specific heat needed for the calculations are in the table below solution beat of (Uinol -164.4 hydrechione acid 4696 sodium hydrode sodium chloride 10) 407.1 RS9 100 sodium nitrate 1.00 3/19 4162 0.5 M sodium chloride+ 0.5 M sodium hydroxide 3.94

Chemistry: The Molecular Science
5th Edition
ISBN:9781285199047
Author:John W. Moore, Conrad L. Stanitski
Publisher:John W. Moore, Conrad L. Stanitski
Chapter13: The Chemistry Of Solutes And Solutions
Section: Chapter Questions
Problem 83QRT
Question
100%

Please help me with the highlighted part, using the pg 138 attachment. This is my digital lab notes not a graded assignment. Thanks in advance! 

Trial 1
Trial 2
Trial 3
Trial 4
Beaker
1st cup 50mL of
50mL of
Mass of empty polystyrene cup
2M HCl
2M NaOH
2M HNO 3
1M HCl
2M NaOH
2M HCl
2M NaOH
2M NaOH
13.94g
14.50g
13.76g
14.19g
Mass of cup + mixture
98.53g
98.86g
98.02g
96.62g
Mass of mixture
84.59g
84.36g
84.26g
82.43g
Initial temp of 1st reagent (from graph)
22.1°C
22.2°C
22.6°C
22.7°C
Final temp of mixture (from graph)
At Temperature change
Total heat evolved in reaction (AHn)
Number of moles of H₂O formed
36.1°C
36.0°C
36.0°C
30.0°C
14°C
13.8°C
13.4°C
7.3°C
4.94 kJ
4.87 kJ
4.72 kJ
2.52 kJ
0.100 mol
0.100 mol
0.100 mol
Limiting
reagent
0.050 mol
Molar heat of neutralization (AH)
-49.4
-48.7
-47.2
-50.4
kJ/mol
kJ/mol
kJ/mol
kJ/mol
Molar heat of neutralization calculated from Hess's
Law and data on pg 138 of lab manual
Percentage difference between experimental and
calculated value (%Diff)
Le AH - best of neutralization
raolar beat of neutralization
temperature charge of solution
mass of final solutice
-specific heat of final solution
number of moles of HCI
AH CA
AH -mC st
AH AHA
Hess's law can be used to calculate the molar heat of neutralization from literature values
for bears of formation of HCI, NaOH NaCl and HO. These values and the specific heat needed for
the calculations are in the table below
solution
beat of
(Uinol
-164.4
hydrechione acid
4696
sodium hydrode
sodium chloride
10)
407.1
RS9
100
sodium nitrate
1.00
3/19
4162
0.5 M sodium chloride+
0.5 M sodium hydroxide
3.94
Transcribed Image Text:Trial 1 Trial 2 Trial 3 Trial 4 Beaker 1st cup 50mL of 50mL of Mass of empty polystyrene cup 2M HCl 2M NaOH 2M HNO 3 1M HCl 2M NaOH 2M HCl 2M NaOH 2M NaOH 13.94g 14.50g 13.76g 14.19g Mass of cup + mixture 98.53g 98.86g 98.02g 96.62g Mass of mixture 84.59g 84.36g 84.26g 82.43g Initial temp of 1st reagent (from graph) 22.1°C 22.2°C 22.6°C 22.7°C Final temp of mixture (from graph) At Temperature change Total heat evolved in reaction (AHn) Number of moles of H₂O formed 36.1°C 36.0°C 36.0°C 30.0°C 14°C 13.8°C 13.4°C 7.3°C 4.94 kJ 4.87 kJ 4.72 kJ 2.52 kJ 0.100 mol 0.100 mol 0.100 mol Limiting reagent 0.050 mol Molar heat of neutralization (AH) -49.4 -48.7 -47.2 -50.4 kJ/mol kJ/mol kJ/mol kJ/mol Molar heat of neutralization calculated from Hess's Law and data on pg 138 of lab manual Percentage difference between experimental and calculated value (%Diff) Le AH - best of neutralization raolar beat of neutralization temperature charge of solution mass of final solutice -specific heat of final solution number of moles of HCI AH CA AH -mC st AH AHA Hess's law can be used to calculate the molar heat of neutralization from literature values for bears of formation of HCI, NaOH NaCl and HO. These values and the specific heat needed for the calculations are in the table below solution beat of (Uinol -164.4 hydrechione acid 4696 sodium hydrode sodium chloride 10) 407.1 RS9 100 sodium nitrate 1.00 3/19 4162 0.5 M sodium chloride+ 0.5 M sodium hydroxide 3.94
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