Please help Trial 1Trial 2Trial 38. Moles of NaOH added (mol)9. Moles of acetylsalicylic acid (mol)10. Mass of acetylsalicylic acid (g)11. Percent purity of aspirin sample (%)12. Average percent purity of aspirin sample (%)13. Calculate the standard deviation for the percentacetylsalicylic acid in aspirin.14. Calculate the relative standard deviation (%RSD). C. Percent Acetylsalicylic Acid in the Aspirin SampleCalculation for the mass of aspirin for the titrimetric analysis. See Part C.1.10. Icom x C. C 2C LX Inel =G,0zmTrial 1Trial 2Trial 31. Mass of weighing paper (g)o4821512443g439582. Mass of weighing paper plus aspirin sample (g)1358 3 6508933. Mass of aspirin sample (g)う64. Molar concentration of the NaOH solution (mol/L)20.13५2.१व्_ १३.२।।23.085. Buret reading, initial (mL)22,0222ML 201976. Buret reading, final (mL)7. Volume of NaOH added (mL)Experiment 19 243

“Since you have posted a question with multiple sub-parts, we will solve the first three sub-parts for you. To get remaining sub-part solved please repost the complete question and mention the sub-parts to be solved.”. The concentration of the unknown substance in a solution can be determined by titrating unknown against the solution whose concentration is well known. There are various concentration units that can be used to denote the concentration of a solution and it includes molarity, molality, mass percent, and volume percent. The number of a substance is determined as the ratio of the mass (M) to its molar mass (MM). Number of moles=MMM ...(1) When the moles of the substance are related to the volume of the solution per liter, it provides the concentration in molarity. 8) Determination of moles of sodium hydroxide: The concentration of the NaOH solution is provided as 0.0893 mol/L. Relate this with the volume of NaOH used to evaluate the moles of sodium NaOH. Trial-1: Number of moles of NaOH=0.0893 mol1000 mL×22 mL=1.96×10-3 molTrial-2: Number of moles of NaOH=0.0893 mol1000 mL×20.97 mL=1.87×10-3 molTrial-3:Number of moles of NaOH=0.0893 mol1000 mL×23.08 mL=2.06×10-3 mol Hence the number of moles of NaOH used in trial-1, trial-2, and trial-3 are calculated as 1.96×10-3 mol, 1.87×10-3 mol, and 2.06×10-3 mol respectively.9) The moles of acetylsalicylic acid are evaluated by relating the mass of acetylsalicylic acid and its molar mass as stated in equation 1. Trial-1:Number of moles of acetylsalicylic acid=0.361 g180.159 g/mol=2.00×10-3 molTrial-2:Number of moles of acetylsalicylic acid=0.358 g180.159 g/mol=1.98×10-3 molTrial-3:Number of moles of acetylsalicylic acid=0.365 g180.159 g/mol=2.02×10-3 mol Hence the number of moles of acetylsalicylic acid used in trial-1, trial-2, and trial-3 are calculated as 2.00×10-3 mol, 1.98×10-3 mol, and 2.02×10-3 mol respectively. 10) From table-C, the mass of the acetylsalicylic acid (aspirin) (m) is evaluated as follows. Trial-1:m=Mass of paper weighed with aspirin-Mass of paper alone=0.843 g-0.482 g=0.361 gTrial-2:m=Mass of paper weighed with aspirin-Mass of paper alone=0.870 g-0.512 g=0.358 gTrial-3:m=Mass of paper weighed with aspirin-Mass of paper alone=0.858 g-0.365 g=0.493 g Hence the mass of acetylsalicylic acid used in trial-1, trial-2, and trial-3 are calculated as 0.361 g, 0.358 g, and 0.493 g respectively.