Trial 1 Trial 2 M of NaOH(aq): Average M of NaOH(aq) from part I M of NaOH(aq): Average M of NaOH(aq) from part I Volume of vinegar: 10.00 mL. Volume of vinegar: 10.00 mL. Initial buret reading of NaOH (aq): 0.00 mL. Initial buret reading of NaOH (aq) : 12.35 mL. Final buret reading of NaOh(aq) pink color: 12.35 mL. Final buret reading of NaOh(aq) pink color: 25.00 mL. Volume of NaOH(aq): Volume of NaOH(aq): Calculations: For each trial : NaOH(aq) + CH3COOH(aq) → NaCH3COO(aq) + H₂O(1) a. Moles of NaOH(aq): volume of NaOH(aq) in L. x average M of NaOH(aq) from part I b. Moles of NaOH → moles of CH3COOH: moles of CH3COOH M of CH3COOH = moles of CH3COOH (b) / volume of vinegar in L. Get average M of CH3COOH (aq): (M+ M)/2 Mass% of CH3COOH in the vinegar solution : Molar mass of CH3COOH = 60.01 g/mole, Density of vinegar solution = 1.10 g/mole Moles of CH3COOH (b) →g of CH3COOH : c: moles of CH3COOH x molar mass of CH3COOH 10.00 mL. vinegar x 1.10 g/mL. = 10.1 g vinegar Mass% of CH3COOH = (g of CH3COOH (c) / 10.1 g vinegar) x 100 Get average of mass% of CH3COOH.
Trial 1 Trial 2 M of NaOH(aq): Average M of NaOH(aq) from part I M of NaOH(aq): Average M of NaOH(aq) from part I Volume of vinegar: 10.00 mL. Volume of vinegar: 10.00 mL. Initial buret reading of NaOH (aq): 0.00 mL. Initial buret reading of NaOH (aq) : 12.35 mL. Final buret reading of NaOh(aq) pink color: 12.35 mL. Final buret reading of NaOh(aq) pink color: 25.00 mL. Volume of NaOH(aq): Volume of NaOH(aq): Calculations: For each trial : NaOH(aq) + CH3COOH(aq) → NaCH3COO(aq) + H₂O(1) a. Moles of NaOH(aq): volume of NaOH(aq) in L. x average M of NaOH(aq) from part I b. Moles of NaOH → moles of CH3COOH: moles of CH3COOH M of CH3COOH = moles of CH3COOH (b) / volume of vinegar in L. Get average M of CH3COOH (aq): (M+ M)/2 Mass% of CH3COOH in the vinegar solution : Molar mass of CH3COOH = 60.01 g/mole, Density of vinegar solution = 1.10 g/mole Moles of CH3COOH (b) →g of CH3COOH : c: moles of CH3COOH x molar mass of CH3COOH 10.00 mL. vinegar x 1.10 g/mL. = 10.1 g vinegar Mass% of CH3COOH = (g of CH3COOH (c) / 10.1 g vinegar) x 100 Get average of mass% of CH3COOH.
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
Related questions
Question
Molarity of NaOH= 0.1018m
![### Titration Data and Calculations
#### Data:
| | **Trial 1** | **Trial 2** |
|-----------------------|---------------------------------------------------------|---------------------------------------------------------|
| **M of NaOH(aq):** | **Average M of NaOH(aq) from part I** | **Average M of NaOH(aq) from part I** |
| **Volume of vinegar:**| 10.00 mL | 10.00 mL |
| **Initial buret reading of NaOH (aq):** | 0.00 mL | 12.35 mL |
| **Final buret reading of NaOH(aq) pink color:** | 12.35 mL | 25.00 mL |
| **Volume of NaOH(aq):** | | |
#### Calculations:
For each trial I:
\[ \text{NaOH}(aq) + \text{CH}_3\text{COOH}(aq) \rightarrow \text{NaCH}_3\text{COO}(aq) + \text{H}_2\text{O}(l) \]
a. **Moles of NaOH(aq):**
- Use the formula `Volume of NaOH(aq) in L × average M of NaOH(aq) from part I`
b. **Moles of NaOH → moles of CH₃COOH:**
- The stoichiometric ratio of NaOH to CH₃COOH is 1:1
\[ \text{M of CH}_3\text{COOH} = \text{moles of CH}_3\text{COOH (b)} / \text{volume of vinegar in L} \]
#### Mass% of CH₃COOH in the Vinegar Solution:
- **Molar mass of CH₃COOH:** 60.01 g/mol
- **Density of vinegar solution:** 1.10 g/mL
Calculate:
- **Volume of vinegar:** 10.00 mL
- **Mass of vinegar:**
\[ 10.00 \text{ mL} \times 1.10 \text{ g/mL} = 10.1 \text{ g vinegar} \]
\[ \text{Mass% of CH}_3\text{COOH} =](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Ffdeaa466-70f4-480d-bd45-ed519d8d81f4%2F56a26360-8364-428e-984a-1f8b0446b2c4%2Fzemth9u_processed.jpeg&w=3840&q=75)
Transcribed Image Text:### Titration Data and Calculations
#### Data:
| | **Trial 1** | **Trial 2** |
|-----------------------|---------------------------------------------------------|---------------------------------------------------------|
| **M of NaOH(aq):** | **Average M of NaOH(aq) from part I** | **Average M of NaOH(aq) from part I** |
| **Volume of vinegar:**| 10.00 mL | 10.00 mL |
| **Initial buret reading of NaOH (aq):** | 0.00 mL | 12.35 mL |
| **Final buret reading of NaOH(aq) pink color:** | 12.35 mL | 25.00 mL |
| **Volume of NaOH(aq):** | | |
#### Calculations:
For each trial I:
\[ \text{NaOH}(aq) + \text{CH}_3\text{COOH}(aq) \rightarrow \text{NaCH}_3\text{COO}(aq) + \text{H}_2\text{O}(l) \]
a. **Moles of NaOH(aq):**
- Use the formula `Volume of NaOH(aq) in L × average M of NaOH(aq) from part I`
b. **Moles of NaOH → moles of CH₃COOH:**
- The stoichiometric ratio of NaOH to CH₃COOH is 1:1
\[ \text{M of CH}_3\text{COOH} = \text{moles of CH}_3\text{COOH (b)} / \text{volume of vinegar in L} \]
#### Mass% of CH₃COOH in the Vinegar Solution:
- **Molar mass of CH₃COOH:** 60.01 g/mol
- **Density of vinegar solution:** 1.10 g/mL
Calculate:
- **Volume of vinegar:** 10.00 mL
- **Mass of vinegar:**
\[ 10.00 \text{ mL} \times 1.10 \text{ g/mL} = 10.1 \text{ g vinegar} \]
\[ \text{Mass% of CH}_3\text{COOH} =
Expert Solution
This question has been solved!
Explore an expertly crafted, step-by-step solution for a thorough understanding of key concepts.
This is a popular solution!
Trending now
This is a popular solution!
Step by step
Solved in 3 steps with 3 images
Knowledge Booster
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, chemistry and related others by exploring similar questions and additional content below.Recommended textbooks for you
Chemistry
Chemistry
ISBN:
9781305957404
Author:
Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:
Cengage Learning
Chemistry
Chemistry
ISBN:
9781259911156
Author:
Raymond Chang Dr., Jason Overby Professor
Publisher:
McGraw-Hill Education
Principles of Instrumental Analysis
Chemistry
ISBN:
9781305577213
Author:
Douglas A. Skoog, F. James Holler, Stanley R. Crouch
Publisher:
Cengage Learning
Chemistry
Chemistry
ISBN:
9781305957404
Author:
Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:
Cengage Learning
Chemistry
Chemistry
ISBN:
9781259911156
Author:
Raymond Chang Dr., Jason Overby Professor
Publisher:
McGraw-Hill Education
Principles of Instrumental Analysis
Chemistry
ISBN:
9781305577213
Author:
Douglas A. Skoog, F. James Holler, Stanley R. Crouch
Publisher:
Cengage Learning
Organic Chemistry
Chemistry
ISBN:
9780078021558
Author:
Janice Gorzynski Smith Dr.
Publisher:
McGraw-Hill Education
Chemistry: Principles and Reactions
Chemistry
ISBN:
9781305079373
Author:
William L. Masterton, Cecile N. Hurley
Publisher:
Cengage Learning
Elementary Principles of Chemical Processes, Bind…
Chemistry
ISBN:
9781118431221
Author:
Richard M. Felder, Ronald W. Rousseau, Lisa G. Bullard
Publisher:
WILEY