Trial 1: Initial pH= 3.92mL Mass of KHP and Paper= 0.868g Mass of paper= 0.357g Mass of KHP= 0.511g Trial 2: Initial pH= 4.09ml Mass of KHP and Paper= 0.870g Mass of paper= 0.359g Mass of KHP= 0.511g 1) find the volume at equivalence point of both trial 2) find the pH at equivalence point of both trial and calculate the molarity of the NaOH solution from each result and calculate the mean.
Trial 1: Initial pH= 3.92mL Mass of KHP and Paper= 0.868g Mass of paper= 0.357g Mass of KHP= 0.511g Trial 2: Initial pH= 4.09ml Mass of KHP and Paper= 0.870g Mass of paper= 0.359g Mass of KHP= 0.511g 1) find the volume at equivalence point of both trial 2) find the pH at equivalence point of both trial and calculate the molarity of the NaOH solution from each result and calculate the mean.
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Question
Trial 1:
Initial pH= 3.92mL
Mass of KHP and Paper= 0.868g
Mass of paper= 0.357g
Mass of KHP= 0.511g
Trial 2:
Initial pH= 4.09ml
Mass of KHP and Paper= 0.870g
Mass of paper= 0.359g
Mass of KHP= 0.511g
1) find the volume at equivalence point of both trial
2) find the pH at equivalence point of both trial and calculate the molarity of the NaOH solution from each result and calculate the mean.
![ph vs. buret reading
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Transcribed Image Text:ph vs. buret reading
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Transcribed Image Text:ph vs. buret reading
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